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3 years ago

Name the following compounds:

Chemistry

2 answers:

lord [1]3 years ago

7 0

Answer :

(a) The name for $NaF$ is sodium fluoride.

(b) The name for $Rb_2O$ is rubidium oxide.

(c) The name for $BCl_3$ is boron trichloride.

(d) The name for $H_2Se$ is dihydrogen selenide.

(e) The name for $P_4O_6$ is tetraphosphorous hexaoxide.

(f) The name for $ICl_3$ is iodine trichloride.

Explanation :

The nomenclature of covalent compound is given by:

1. The less electronegative element is written first.

2. The more electronegative element is written then, and a suffix is added with it. The suffix added is '-ide'.

3. If atoms of an element is greater than 1, then prefixes are added which are 'mono' for 1 atom, 'di' for 2 atoms, 'tri' for 3 atoms and so on..

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in front of positive ions.

(a) $NaF$ is an ionic compound because sodium element is a metal and fluorine element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

So, the name for $NaF$ is sodium fluoride.

(b) $Rb_2O$ is an ionic compound because rubidium element is a metal and oxygen element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

So, the name for $Rb_2O$ is rubidium oxide.

(c) $BCl_3$ is a covalent compound because boron and chlorine element is a non-metal. The bond formed between the non-metal is always covalent in nature.

So, the name for $BCl_3$ is boron trichloride.

(d) $H_2Se$ is a covalent compound because hydrogen and selenium element is a non-metal. The bond formed between the non-metal is always covalent in nature.

So, the name for $H_2Se$ is dihydrogen selenide.

(e) $P_4O_6$ is a covalent compound because phosphorous and oxygen element is a non-metal. The bond formed between the non-metal is always covalent in nature.

So, the name for $P_4O_6$ is tetraphosphorous hexaoxide.

(f) $ICl_3$ is a covalent compound because iodine and chlorine element is a non-metal. The bond formed between the non-metal is always covalent in nature.

So, the name for $ICl_3$ is iodine trichloride.

timama [110]3 years ago

6 0

A) sodium fluoride
B) rubidium oxide
C) boron trichloride
D) dihydrogen selenide
E) tetraphosphate hexoxide
F) iodine trichloride

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First we have to calculate the moles of $N_2$ and $H_2$ .

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From the balanced reaction we conclude that

As, 1 mole of $N_2$ react with 3 mole of $H_2$

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From this we conclude that, $H_2$ is an excess reagent because the given moles are greater than the required moles and $N_2$ is a limiting reagent and it limits the formation of product.

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