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Akimi4 [234]
3 years ago
13

Henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. He will get a second turn if he rolls a s

um that is an even number less than 10.
What are Henry's chances of getting a second turn when he rolls the number cubes?

A.seven over eighteen
B.11 over 18
C.5 over 36
D.17 over 36
Mathematics
2 answers:
rusak2 [61]3 years ago
4 0

1. There are 6·6=36 possible outcomes of rolling two number cubes.

2. He must roll the sum 2, 4, 6, 8.

To roll 2 he has 1 chance - (1,1) {here ordered pair (i,j) means that i is the number rolled on 1st cube and j is the number rolled on 2nd cube}.

To roll 4 he has 3 chances - (1,3), (2,2) and (3,1).

To roll 6 he has 5 chances - (1,5), (2,4), (3,3), (4,2) and (5,1).

To roll 8 he has 5 chances - (2,6), (3,5), (4,4), (5,3) and (6,1).

In total 1+3+5+5=14 possible favorable outcomes.

Then his chances of getting a second turn when he rolls the number cubes are 14:36=7:18.

Answer: correct choice is A

xeze [42]3 years ago
4 0

Answer:

The answer is A, 7/18.

Step-by-step explanation:

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Answer:

A

Step-by-step explanation:

We want to solve the equation:

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To do so, we can rewrite the equation.

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By substitution:

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And factor:

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Hence, our answer is A.

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