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In-s [12.5K]
3 years ago
14

Megan experimented with growing mold. She took 3 pieces of bread from the same loaf and placed each into a plastic sandwich bag.

Before sealing the bag, she added 5 drops of water to each slice. Next, she placed one bag on her window sill, one in a dark cabinet, and one in a room away from sunlight. Megan concluded that the different amount of mold that grew on each slice was due to the amount of light it received. Is this a valid conclusion?
A) Yes, because the light was the manipulated variable.


B) Yes, because the light was the controlled variable.


C) No, because the light could not have affected the growth.


D) No, because the light should have been the same for each bread slice.
Chemistry
2 answers:
kvasek [131]3 years ago
3 0

Answer:

Yes, because the light was the manipulated variable

Explanation:

djyliett [7]3 years ago
3 0

Answer:

Your answer would be A. Yes, because the light was the manipulated variable.

Explanation:

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Answer: No, a<span>t high pressures, volume of a real gas does not  compare with the volume of an ideal gas under the same conditions.

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Which particle changes to create an isotope of an atom? <br> A.proton<br> B.neutron<br> C.electron
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Ivahew [28]

The concentration of the hydroxide ions, OH¯ in 250 mL of the solution containing the maximum amount of dissolved calcium hydroxide is 0.01728 M

We'll begin by calculating the number of mole of in 0.16 g of Ca(OH)₂. This can be obtained as follow:

Mass of Ca(OH)₂ = 0.16 g

Molar mass of Ca(OH)₂ = 40 + 2[16 + 1] = 74 g/mol

<h3>Mole of Ca(OH)₂ =? </h3>

Mole = mass / molar mass

Mole of Ca(OH)₂ = 0.16 / 74

<h3>Mole of Ca(OH)₂ = 0.00216 mole </h3>

  • Next, we shall determine the molarity of the stock solution of Ca(OH)₂.

Mole of Ca(OH)₂ = 0.00216 mole

Volume = 100 mL = 100 / 1000 = 0.1 L

<h3>Molarity of Ca(OH)₂ =? </h3>

Molarity = mole / Volume

Molarity of Ca(OH)₂ = 0.00216 / 0.1

<h3>Molarity of Ca(OH)₂ = 0.0216 M</h3>

  • Next, we shall determine the molarity of the diluted solution. This can be obtained as follow:

Volume of stock solution (V₁) = 100 mL

Molarity of stock solution (M₁) = 0.0216 M

Volume of diluted solution (V₂) = 250 mL

<h3>Molarity of diluted solution (M₂) =?</h3>

<h3>M₁V₁ = M₂V₂</h3>

0.0216 × 100 = M₂ × 250

2.16 = M₂ × 250

Divide both side by 250

M₂ = 2.16 / 250

<h3>M₂ = 0.00864 M</h3>

Thus, the molarity of the diluted solution is 0.00864 M

  • Finally, we shall determine the concentration of the hydroxide ions, OH¯ in the diluted solution. This can be obtained as follow:

Ca(OH)₂(aq) —> Ca²⁺(aq) + 2OH¯(aq)

From the balanced equation above,

1 mole of Ca(OH)₂ contains 2 moles of OH¯

Therefore,

0.00864 M Ca(OH)₂ will contain =  2 × 0.00864 = 0.01728 M OH¯

Thus, the concentration of the hydroxide ions, OH¯ in 250 mL of the solution containing the maximum amount of dissolved calcium hydroxide is 0.01728 M

Learn more: brainly.com/question/11471182

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False, b/c you can't turn electricity into a fuel 
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