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In-s [12.5K]
3 years ago
14

Megan experimented with growing mold. She took 3 pieces of bread from the same loaf and placed each into a plastic sandwich bag.

Before sealing the bag, she added 5 drops of water to each slice. Next, she placed one bag on her window sill, one in a dark cabinet, and one in a room away from sunlight. Megan concluded that the different amount of mold that grew on each slice was due to the amount of light it received. Is this a valid conclusion?
A) Yes, because the light was the manipulated variable.


B) Yes, because the light was the controlled variable.


C) No, because the light could not have affected the growth.


D) No, because the light should have been the same for each bread slice.
Chemistry
2 answers:
kvasek [131]3 years ago
3 0

Answer:

Yes, because the light was the manipulated variable

Explanation:

djyliett [7]3 years ago
3 0

Answer:

Your answer would be A. Yes, because the light was the manipulated variable.

Explanation:

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Answer:

B. 120 cm

Explanation:

The scale is 1 to 15, so when we are given the value of 8cm all you have to do it multiply 8 by 15 which leaves you with 120.

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7 0
3 years ago
Give examples of two properties of water that are caused by the attractions between water molecules.
solniwko [45]
1. Waters high heat of evaporation.
2. Waters high polarity.
8 0
3 years ago
A chemical reactions occurs when, _____?
bixtya [17]

Answer:

Reactants are transformed into products

Explanation:

Chemical reactions are happening everywhere, it may be represented by the following equation:

A(aq) + B(s) ⇒ C(g) + D(l)

The left side represent the reactants that interact to get the products.

In the parenthetycal note is the state of the compound, in this case, aquose solution (aq), solid (s), gas (g), liquid (l)

7 0
4 years ago
An 11.2 L sample of gas is determined to contain 0.5 moles of nitrogen. At the same temperature and pressure, how many moles of
Volgvan

Answer:

0.89 moles of N2 gas

Explanation:

From Avogadro's law:

V1/n1 = V2/n2

n2 = V2n1/V1

V1=11.2L

V2= 20L

n1=0.5 moles

n2 = ??

Therefore

n2= 20×0.5/11.2= 0.89 moles

8 0
3 years ago
Read 2 more answers
It takes 42.25 ml of 0.0500 M Na2S2O3 solution to completely react with the iodine present in a 150.0 ml iodine solution. How ma
svlad2 [7]

Answer:

There were 0.268 grams I2 present

Explanation:

Step 1: Data given

Volume of Na2SO3 = 42.25 mL = 0.04225 L

Molarity of Na2SO3 = 0.0500 M

Volume of iodine = 150.0 mL

Step 2: The balanced equation

I2 + 2 Na2SO3 → Na2S2O6 + 2 NaI

Step 3: Calculate moles of Na2SO3

Moles Na2SO3 = molarity * volume

Moles Na2SO3 = 0.0500 M * 0.04225 L

Moles Na2SO3 = 0.0021125 moles

Step 4: Calculate moles I2

For 1 mol I2 we need 2 moles Na2SO3

For 0.0021125 moles Na2SO3 we have 0.00105625

Step 5: Calculate mass of I2

Mass I2 = moles * molar mass

Mass I2 = 0.00105625 * 253.8 g/mol

Mass I2 = 0.268 grams

There were 0.268 grams I2 present

3 0
3 years ago
Read 2 more answers
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