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2 years ago

10

Question 6 (4 points)

2 answers:

pishuonlain [190]2 years ago

8 0

Answer:

20.9%

Explanation:

I took the test i hope this helps:)

Afina-wow [57]2 years ago

5 0

Answer:

B, "20.9%"

Explanation:

I also took the test.

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Why is the stability of a compound considered a chemical property?

Tcecarenko [31]

Chemical property is the ability of a substance to react with other substances or to transform into other substances. The stability of a compound indicates how much it "prefers" to remain as such or to get transformed. Then the stability is a chemical property.

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3 years ago

Read 2 more answers

The standard molar heat of fusion of ice is 6020 j/mol. calculate q, w, and ∆e for melting 1.00 mol of ice at 0◦c and 1.00 atm p

zysi [14]

Answer : q = 6020 J, w = -6020 J, Δe = 0

Solution : Given,

Molar heat of fusion of ice = 6020 J/mole

Number of moles = 1 mole

Pressure = 1 atm

Molar heat of fusion : It is defined as the amount of energy required to melt 1 mole of a substance at its melting point. There is no temperature change.

The relation between heat and molar heat of fusion is,

$q=\Delta H_{fusion}(\frac{Mass}{\text{ Molar mass}})$ (in terms of mass)

or, $q=\Delta H_{fusion}\times Moles$ (in terms of moles)

Now we have to calculate the value of q.

$q=6020J/mole\times 1Mole=6020J$

When temperature is constant then the system behaves isothermally and Δe is a temperature dependent variable.

So, the value of $\Delta e=0$

Now we have to calculate the value of w.

Formula used : $\Delta e=q+w$

where, q is heat required, w is work done and $\Delta e$ is internal energy.

Now put all the given values in above formula, we get

$0=6020J+w$

w = -6020 J

Therefore, q = 6020 J, w = -6020 J, Δe = 0

3 0

3 years ago

What is a rechargeable battery?

aleksklad [387]

Answer:

a group of electrochemical cells that can be recharged

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3 years ago

What is the half-life of A? What will the pressure, initially 32.1 kPa, at

kodGreya [7K]

Answer:

a) 32.09 kPa

b) 32.09 kPa

Explanation:

Given data:

rate constant $= 3.56\times 10^{-7} s^{-1}$

initial pressure is = 32.1 kPa

half life of A is calculated as

$t_{1/2} = \frac{ln 2}{k}$

$t_{1/2} = \frac{ln 2}{3.56\time 10^{-7}}$

$t_{1/2} = = 1.956 \times 10^6 s$

for calculating pressure we have follwing expression

$ln p = ln P_o - kt$

$P =P_o e^{-kt}$

a) $P = 32.1 e^{-3.56\times 10^{-7} \times 10} = 32.09 kPa$

b) $P = 32.1 e^{-3.56\times 10^{-7} \times 10\times 60} = 32.09 kPa$

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3 years ago

The major products obtained from the following sequence of reactions are:

dmitriy555 [2]

Answer:

The answer is "Option C".

Explanation:

Please find the complete question and its solution in the attached file.

using Hoffman's elimination reaction.

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3 years ago