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Alona [7]
3 years ago
13

Which equation represents the combined gas law?

Chemistry
1 answer:
Keith_Richards [23]3 years ago
8 0
<span>((P1V1/T1)=(P2V2/T2))</span>
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7 0
3 years ago
PLZ HELP, GIVING BRAINLIEST!!
andrew-mc [135]

Answer:

Option B. Decreasing the temperature of the solvent

Explanation:

Solubility is mostly enhanced by increasing the temperature of the solvent or solution. This means that am increase in temperature will increase the solubility and decreasing the temperature will decrease the solubility.

5 0
3 years ago
Read 2 more answers
What mass of H2 is needed to react with 8.75 g of O2 according to the following equation: O2(g) + H2(g) → H2O(g)?
alina1380 [7]

Mass of H₂ needed to react with O₂ : 1.092 g

<h3>Further explanation</h3>

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Reaction

O₂(g) + 2H₂(g) → 2H₂O(g)

mass of O₂ : 8.75 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{8.75}{32}=0.273

From the equation, mol ratio of O₂ : H₂ = 1 : 2, so mol H₂ :

\tt \dfrac{2}{1}\times 0.273=0.546

Mass H₂ (MW=2 g/mol) :

\tt 0.546\times 2=1.092~g

4 0
3 years ago
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Match these items with their examples.
postnew [5]
Salt=compound, soda=liquid solution, aluminum foil=element, milk=colloid,
steel=solid solution
8 0
3 years ago
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The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
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