4 years ago

Can someone help me solving this equation for x please

1 answer:

6 0

Answer:

±2/11

Step-by-step explanation:

Take the square root of both sides of the equation:

$\sqrt{x^2}=\sqrt{\dfrac{4}{121}}\\\\\boxed{x=\pm\dfrac{2}{11}}$

_____

Here, we need to recognize that (-2/11)^2 = (2/11)^2 = 4/121, so both the positive and negative roots of 4/121 are solutions to the equation.

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Vsevolod [243]

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vodomira [7]

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3 years ago

Elanso [62]

This would probably be B.

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ryzh [129]

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