All categories

3 years ago

A spring requires a force of 25 n to produce an extension of 2 cm in it. what is the work done in further extending it by 3 cm

Chemistry

2 answers:

damaskus [11]3 years ago

7 0

Answer: The work done in further extending spring by 3 cm is 0.5625 Joules.

Explanation:

Force exerted on spring,F = 25 N

Distance up to which spring stretched ,x= 2 cm = 0.02 m

(1 m = 100 cm)

$F=kx$

$k=\frac{F}{x}=\frac{25 N}{0.02 m}=1250 N/m$

Work done while further stretching the spring by distance x' = 3 cm.

Work done = $\frac{1}{2}k\times x'^2=\frac{1}{2}\times 1250 N/m\times (3\times 10^{-2} m)^2=0.5625 N m=0.5625 Joules$

The work done in further extending spring by 3 cm is 0.5625 Joules.

Sonbull [250]3 years ago

4 0

The force of a spring can be calculated by the expression:

F = kx where k is a constant and x is the distance.

From the problem statement, we can solve the value of k from the initial conditions given as F = 25 N and x = 2 cm.

25 = k (0.02)
k = 1250

We use the work formula which is force times the distance resulting to the expression:

W = (1/2)(kx^2)
W = (1/2)(1250)(0.03^2)
W = 0.5625 J

You might be interested in

Express the following in regular notation:

dusya [7]

A because if you multiple it, you will be moving the decimal one time

8 0

3 years ago

What experimental observations indicate a gas is being released?

joja [24]

Answer:

new substances formed, as evidenced by the color changes and bubbles. Some signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color chage, formation of a precipitate, formation of a gas, odor change, temperature change.

HOPE THIS HELPED!!!!!!!!!!!!!!XDDDDDDDDDD

3 0

3 years ago

An element's atomic number is 65. How many protons would an atom of this element have?

KIM [24]

65. The atomic number is the number of protons in the atom.

7 0

3 years ago

Science pls helppp?!

hichkok12 [17]

Answer:

2nd one down

Explanation: distance divided by time interval

6 0

3 years ago

Read 2 more answers

Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C

Leno4ka [110]

Explanation:

The reaction equation will be as follows.

$C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)$

Using bond energies, expression for calculating the value of $\Delta H$ is as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

On reactant side, from $C_{2}H_{6}$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From $Cl_{2}$ ; Cl-Cl bonds = 1

On product side, from $C_{2}H_{5}Cl$ number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

$\Delta H = \sum B.E_{reactants} - \sum B.E_{products}$

= $[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]$ = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0

3 years ago