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2 years ago

10

Why is it important to remove nitrogen and phosphorus from raw sewage?

1 answer:

matrenka [14]2 years ago

4 0

Nitrogen and phosphorus leaked into the water systems increase nutrients available for algae, leading to eutrophication. Because of the amount of algae growing in water systems, bacteria use up a huge amount of oxygen during metabolism in order to clear away the algae. As a result there is much less oxygen available for other living things , and thus their oxygen requirement can not be met , and consequently there is a mass death of these organisms.

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Copy and balance these chemical equations "K

alexdok [17]

"K" is Potassium. If that is the answer you are needing.

5 0

2 years ago

2p is the correct representation for the sub-shell with n = 2 and l = 1.

boyakko [2]

Explanation:

Principle Quantum Numbers : It describes the size of the orbital and the energy level. It is represented by n. Where, n = 1,2,3,4....

Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...

s = 1 orbital

p = 3 orbitals

d = 5 orbitals

f = 7 orbitals

For n = 4

l = 0 to (n-1) = 0 to 3 = (4s , 4p , 4d , 4f)

Number of subshells = 4

Number of orbitals = 1 + 3 + 5 + 7 = 16

The maximum number of electrons the n = 4 shell can contain:

Each orbital can holds upto two electrons, then 16 orbitals will have :

$16\times 2=32$

32 is the maximum number of electrons the n = 4 shell can contain

6 0

3 years ago

Read 2 more answers

A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? A

anygoal [31]

this is a dilution equation where 50.0 mL of 1.50 M H₂SO₄ is taken and added to 200 mL of water.

c1v1 = c2v2

where c1 is concentration and v1 is volume of the concentrated solution

and c2 is concentration and v2 is volume of the diluted solution to be prepared

50.0 mL of 1.50 M H₂SO₄ is added to 200 mL of water so the final solution volume is - 200 + 50.0 = 250 mL

substituting these values in the formula

1.50 M x 50.0 mL = C x 250 mL

C = 0.300 M

concentration of the final solution is A) 0.300 M

4 0

3 years ago

Read 2 more answers

How many moles of H2 can be made from complete reaction of 3.0 moles of Al?

tresset_1 [31]

Answer: 4.5 moles of $H_{2}$ can be made from complete reaction of 3.0 moles of Al.

Explanation:

The given reaction equation is as follows.

$2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}$

This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.

Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of $AlCl_{3}$ and $\frac{9}{2}$ moles of $H_{2}$ .

The reaction equation now will be as follows.

$3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}$

The moles $\frac{9}{2}$ can also be written as 4.5 moles.

Thus, we can conclude that 4.5 moles of $H_{2}$ can be made from complete reaction of 3.0 moles of Al.

6 0

2 years ago

What are four everyday items that rely on the behavior of gases to operate properly?

Artist 52 [7]

A stove needs gas to burn (I only have one off the top of my head, sorry :/)

6 0

3 years ago