The mass of NaCl formed is 8.307 grams
<u><em> calculation</em></u>
step 1: write the equation for reaction
Na₂CO₃ + 2HCl → 2 NaCl +CO₂ +H₂O
Step 2: find the moles of Na₂CO₃
moles = mass/molar mass
The molar mass of Na₂CO₃ is = (23 x2) + 12 + ( 16 x3) = 106 g/mol
moles = 7.5 g/106 g/mol =0.071 moles
Step 3: use the mole ratio to determine the mole of NaCl
Na₂CO₃:NaCl is 1:2 therefore the moles of NaCl =0.07 x2 =0.142 moles
Step 4: calculate mass of NaCl
mass= moles x molar mass
the molar mass of NaCl= 23 +35.5 =58.5 g/mol
mass = 0.142 moles x 58.5 g/mol =8.307 grams
Answer:
600 mAh·g−1
Explanation:
i hope this is good let me know if its wrong
<span>1.18 x 3 = 3.55 </span>
find ratio of F to F in each compound
. according to law of multiple proportions that the masses of one element which combine with a fixed mass of the second element are in a ratio of whole numbers.
now F is "one element" and S has "fixed mass",
the ratio of F6 to Fx = 3:1
<span>thats why x= 2
there is less F in SFx
the ratio is 3:1.
dividing 6 by 3 and you get 2</span>
Their proton and electron numbers are same