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jek_recluse [69]
3 years ago
10

28 -4a = 3a -14+2a ------

Mathematics
2 answers:
Greeley [361]3 years ago
6 0
24+14 = 3a + 4a +2a
38 = 9a
——————————
Hope it is helpful.
Lubov Fominskaja [6]3 years ago
6 0

\huge\text{Hey there!}

\huge\textsf{28 - 4a = 3a - 14 + 2a}

\huge\boxed{\rightarrow}\huge\textsf{ 28 - 4a = 5a - 14}

\huge\boxed{\rightarrow}}\huge\textsf{ -4a + 28 = 5a - 14}

\huge\text{SUBTRACT \underline{\underline{5a}} to  BOTH SIDES}

\huge\textsf{-4a + 28 - 5a = 5a - 14 - 5a}

\huge\boxed{\rightarrow}\huge\textsf{ -9a + 28 = -14}

\huge\text{SUBTRACT \underline{\underline{28}} to BOTH SIDES}

\huge\textsf{-9a + 28 - 28 = -14 - 28}

\huge\boxed{\rightarrow}}\huge\textsf{ -9a = -42}

\huge\text{DIVIDE \underline{\underline{-9}} to BOTH SIDES}

\huge\boxed{\mathsf{\dfrac{-9a}{-9}=\dfrac{-42}{-9}}}

\huge\boxed{\rightarrow}\huge\boxed{\star\ \mathsf{\ a = \dfrac{14}{3}}\ \star}

\huge\boxed{\mathsf{Therefore, your \ answer\  is: a = \bf \dfrac{14}{3} }}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\huge\boxed{\frak{Amphitrite1040:)}}

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Oksanka [162]
No but it equals to 7 :)
3 0
2 years ago
Read 2 more answers
Find an equation for the line with slope m through the point (a,c).
lidiya [134]
If you want the answer in point slope form then,

y-y1 = m(x-x1)
y-c = m(x-a)

---------------------------------------

If you want the answer in slope intercept form, then solve for y

y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)

For this answer in slope intercept form the slope is m and the y intercept is c-ma

---------------------------------------

If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.

y = mx+c-ma
y-mx = mx+c-ma-mx
-mx+y = c-ma

Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.

4 0
3 years ago
Please help plz and explain
Liono4ka [1.6K]

Answer:

letter d or b

srry if wrong hope thiss helped

8 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Consider the functions given below. SEE F
Wewaii [24]

Answer:

1. P(x) ÷ Q(x)---> \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x)---> \frac{2(6x - 1)}{(3x - 1)(-3x + 2)}

3.  P(x) - Q(x)---> \frac{-2(12x - 5)}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) --> \frac{12}{(3x - 1)(-3x + 2)}

Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

Q(x) = \frac{6}{-3x + 2}

Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

\frac{2}{3x - 1}*\frac{-3x + 2}{6}

\frac{2(-3x + 2)}{6(3x - 1)}

= \frac{-3x + 2}{3(3x - 1)}

2. P(x) + Q(x) = \frac{2}{3x - 1} + \frac{6}{-3x + 2}

Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

\frac{2(-3x + 2) + 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 + 18x - 6}{(3x - 1)(-3x + 2)}

\frac{-6x + 18x + 4 - 6}{(3x - 1)(-3x + 2)}

\frac{12x - 2}{(3x - 1)(-3x + 2)}

= \frac{2(6x - 1}{(3x - 1)(-3x + 2)}

3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

\frac{2(-3x + 2) - 6(3x - 1)}{(3x - 1)(-3x + 2)}

\frac{-6x + 4 - 18x + 6}{(3x - 1)(-3x + 2)}

\frac{-6x - 18x + 4 + 6}{(3x - 1)(-3x + 2)}

\frac{-24x + 10}{(3x - 1)(-3x + 2)}

= \frac{-2(12x - 5}{(3x - 1)(-3x + 2)}

4. P(x)*Q(x) = \frac{2}{3x - 1}* \frac{6}{-3x + 2}

P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

P(x)*Q(x) = \frac{12}{(3x - 1)(-3x + 2)}

4 0
3 years ago
1. Adjacent angles are two angles in the same plane with a common
stepan [7]

Answer:

Adjacent angles are two angles in the same plane with a common  <u>VERTEX</u> and a common  <u>SIDE</u> but no common interior points.

Step-by-step explanation:

Adjacent angles share a common side on the same vertes, but they do not overlap each other.

In the attached image, ∠ABD is adjacent to ∠DBC, but ∠ABC is not adjacent to any of them.

4 0
3 years ago
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