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timurjin [86]
3 years ago
15

Suppose you just received a shipment of fourteen televisions. Three of the televisions are defective. If two televisions are ran

domly​ selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not​ work?
Mathematics
1 answer:
Cloud [144]3 years ago
3 0

Answer with explanation:

Given : Total number of televisions received = 14

Number of defective televisions = 3

Probability of defective televisions :\dfrac{3}{11}

Now, If two televisions are randomly​ selected,  then the probability that both televisions work.

P(0)=(1-\frac{3}{11})^2\approx0.5289

Hence, the probability that both televisions work is 0.5289 .

The probability at least one of the two televisions does not​ work will be :-

P(X\geq1)=1-P(0)=1-0.5289\approx0.4711

Hence, the probability at least one of the two televisions does not​ work is 0.4711.

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