Question

Solve question number 21

Answer 1

Answer:

∝ = 60.50°

Step-by-step explanation:

$AC = \sqrt{AB^{2} + BC^{2} } = \sqrt{128} \\\\AM = \frac{AC}{2} = \frac{\sqrt{128} }{2}$

∡VAM = ∝

$tg \alpha = \frac{VM}{AM} = \frac{10}{\frac{\sqrt{128} }{2} } = 1.76776695297$

$\alpha = arctan (1.76776695297) = 60.50$