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g100num [7]
3 years ago
9

The purity of gold is listed in karats. If a necklace is 75% what karat is it

Mathematics
1 answer:
MrMuchimi3 years ago
5 0
3/4 is gold the rest is not r
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The scale of a map says that 4 cm represents 5 km.
andriy [413]

Answer:

a. 3.2 cm

b. 6.25 km

Step-by-step explanation:

a.

(4 km)/(5 km) = 0.8

4 km is 0.8 of 5 km, so in the map it is 0.8 of 4 cm.

0.8 * 4 cm = 3.2 cm

Answer: 3.2 cm

b.

(5 cm)/(4 cm) = 1.25

5 cm is 1.25 times 4 cm, so it represents 1.25 * 5 km.

1.25 * 5 km = 6.25 km

Answer: 6.25 km

3 0
3 years ago
Find the area and circumference of the 2 circles​
velikii [3]

Answer:

32, 45

Step-by-step explanation:

4 0
2 years ago
PLSSS HURRY!!!!!!!!
Vikki [24]

Answer:

A) x=5 or -11

Step-by-step explanation:

The given equation is:

(x+3)^2=64

The most suitable method so solve this quadratic equation is the square root method.

We take square root of both sides to obtain:

x+3=\pm \sqrt{64}

\implies x+3=\pm8

\implies x=-3\pm8

We now split the plus or minus sign to get;

x=-3-8\:,x=-3+8

This simplifies to:

x=-11\:,x=5

The correct choice is A

6 0
3 years ago
In one lottery, a player wins the jackpot by matching all five numbers drawn from white balls (1 through 41) and matching the nu
puteri [66]

Answer:

1 / 2,787,760,560

Step-by-step explanation:

The number of permutations is:

41 × 40 × 39 × 38 × 37 × 31 = 2,787,760,560

So the probability of winning the jackpot is 1 / 2,787,760,560.

6 0
3 years ago
Callaway is thinking about entering the golf ball market. The company will make a profit if its market share is more than 20%. A
Vedmedyk [2.9K]

Answer:

z=\frac{0.224 -0.2}{\sqrt{\frac{0.2(1-0.2)}{624}}}=1.499  

p_v =P(Z>1.499)=0.0669  

If we compare the p value obtained and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly higher than 0.2 or 20%.  

Step-by-step explanation:

How would you make the decision if you were Callaway management? Would you use hypothesis testing?

The best way to test the claim if with a proportion test. The procedure is explained below.

1) Data given and notation

n=624 represent the random sample taken

X=140 represent the golf ball purchasers will buy a Callaway golf ball

\hat p=\frac{140}{624}=0.224 estimated proportion of golf ball purchasers will buy a Callaway golf ball

p_o=0.2 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is more than 0,2 or 20%:  

Null hypothesis:p\leq 0.2  

Alternative hypothesis:p > 0.2  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.224 -0.2}{\sqrt{\frac{0.2(1-0.2)}{624}}}=1.499  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided but let's assume \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.499)=0.0669  

If we compare the p value obtained and the significance level assumed \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly higher than 0.2 or 20%.  

8 0
3 years ago
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