How do i simplify 14/24.

1 answer:

8 0

Simplify 14/24 to the simplest form - Fractions Simplifier. Use this fractions simplifier calculator to reduce any fraction to lowest terms. You just need to enter the numerator and denominator values. The answer will be a proper fraction or a mixed number and also the decimal equivalent to the given fraction.

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Round 789 to the nearest 10

elena-14-01-66 [18.8K]

Rounding 789 nearest to tens will be 790.

Step-step Explanation:

Let's know how to round any number nearest to tens (Rules):-

We know tens place in any no. from left is at second place and number right to tens place need to be changed as:-

If last digit is 0, then we don't have to do any rounding, because it is already to the ten.

We round the no. down to the nearest ten if the last digit in the no. is 1, 2, 3, or 4

We round the no. up to the nearest ten if the last digit in the no. is 5, 6, 7, 8, or 9.

3 0

2 years ago

Graph y = -1/3x + 3<br><br> (( if you could include a picture of the graph that would be great))

Kay [80]

A place I go to graph is go to desmos. It works well for this. All you have to do is snip the picture of your graph

6 0

3 years ago

0.4612 rounded to the nearest hundredth= what percentage?

Vlad [161]

Question:Round the decimal to the nearest hundredth;then write it as a percentage

<span>Problem: 0.4612=___(<rounded)=___(<percentage)

</span>0.4612 =~ 0,46 (rounded) = 0,46 = 46 (percentage)

7 0

3 years ago

Holly invested £3000 in a savings account the account paid compound interest of 4% per year work out how much was in the account

pogonyaev

Exponential function
form of interest rates

P(1 + r)^x
where p is the prime and r is rate of change and x is time in years

3000(1 + 4%)^1
The answer would be
3000(1.04)^1 = 3120 Euros

3 0

3 years ago

Write the equation of a hyperbola with vertices (0, -4) and (0, 4) and foci (0, -5) and (0, 5).

andre [41]

Check the picture below. So, more or less looks like so.

notice, the center is clearly at the origin, and notice how long the "a" component is, also, bear in mind that, is opening towards the y-axis, that means the fraction with the "y" variable is the positive one.

Also notice, the "c" distance from the center to either foci, is just 5 units.

$\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{{{ a }}^2+{{ b }}^2}
\end{cases}\\\\
-------------------------------\\\\$

$\bf \begin{cases}
h=0\\
k=0\\
a=4\\
c=5
\end{cases}\implies \cfrac{(y-{{ 0}})^2}{{{ 4}}^2}-\cfrac{(x-{{ 0}})^2}{{{ b}}^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{b^2}=1
\\\\\\
c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\\\\\\
\sqrt{5^2-4^2}=b\implies \boxed{3=b}
\\\\\\
\cfrac{y^2}{16}-\cfrac{x^2}{3^2}=1\implies \boxed{\cfrac{y^2}{16}-\cfrac{x^2}{9}=1}$

7 0

3 years ago