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zlopas [31]
3 years ago
7

Oceanic lithosphere is lighter than continental lithosphere. True or False

Physics
1 answer:
seraphim [82]3 years ago
4 0

Answer:

FALSE

Explanation:

The earth's lithosphere is divided into 2 types, namely the continental and the oceanic crust. The continental crust is comprised of lighter rock minerals such as silicate minerals, alkali and potash feldspar, and some oxide minerals, whereas, the oceanic crust is comprised of olivine, pyroxene and some feldpars that are comparatively denser than the minerals present in the continental crust. Due to this composition, the oceanic lithosphere is denser than the continental lithosphere.

During the convergent plate motion, the oceanic lithosphere (plate) subducts below the continental lithosphere due to its greater density.

Thus, the above given statement is False.

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a. A rectangular pen is built with one side against a barn. 1900 m of fencing are used for the other three sides of the pen. Wha
Natalka [10]

Answer:

475 m , 950 m

Explanation:

Let l be the length of the side perpendicular to the barn.

1900-2l = length of the side parallel to the barn

Area A= l( 1900-2l)

A= 1900l-2l^2

now, the maximum value of l ( the equation being quadratic)

l_max= -b/2a

a= 2

b=1900

l_max= -1900/4= 475 m

then 1900-2l= 1900-2×(475) = 950 m

So, the dimensions that maximize area are

950 and 475

Now. A_max = -2( l_max)^2+1900×l_max

A_max=  -2(475)^2+1900×475

A_max= 451250 m^2

or, 475×950 = 451250 m^2

6 0
4 years ago
A loop circuit has a resistance of R1 and a current of 1.8 A. The current is reduced to 1.6 A when an additional 3.8 Ω resistor
Allisa [31]

Answer:

Value of R_1=30.4ohm

Explanation:

We have given

In first case resistance is R_1 and current is 1.8 A

Let the potential difference is v

So 1.8=\frac{v}{R_1}----eqn 1

In second case resistance is R_1+3.8 and current is 1.6 A and potential difference will be as it is a series connection

So 1.6=\frac{v}{R+3.8}----eqn 2

From eqn 1 and eqn 2

1.8R_1=1.6R_1+6.08

R_1=30.4ohm

6 0
3 years ago
Read 2 more answers
A car with mass 1500 kg moves with constant velocity of 36 m/s. The driver sees a group of cows in front and he immediately step
Crazy boy [7]
From laws of motion:

S = ( \frac{v + u}{2} ) \times t
Where S is the distance/displacement (as you would call it) which is unknown
v = final velocity which is 0m/s (this is because the car stops)
u = initial velocity which is 36m/s (from the data given)
t = time taken for the distance to be covered and it is 6s


Substitute the values, hence:
S = ( \frac{0 + 36}{2} ) \times 6
S = (18) \times 6 \\  \\ S = 108m

But this is merely the distance he travelled in the 6 seconds he was trying to stop the car.

Therefore, the distance between the car and the cows = 160-108
Distance = 52m
6 0
4 years ago
If the moon is rising at midnight, the phase of the moon must be
Nadya [2.5K]
The phase is called 3rd quarter.

Hope this helps:)
7 0
4 years ago
An object with a mass of 70 kilograms is supported at a height 8 meters above the ground. What's the potential energy of the obj
alexira [117]
Ep= mgh

70 x 9.8 x 8

Ep= 5,488J
5 0
3 years ago
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