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Serjik [45]
3 years ago
10

An ideal pendulum is often discussed when studying simple harmonic motion. What are the conditions needed for an ideal pendulum?

Check all that apply.
Physics
2 answers:
tamaranim1 [39]3 years ago
8 0

Answer:

Gravitational force acts to pull the pendulum’s mass down.

The pivot on which the pendulum swings is frictionless.

The pendulum swings through its equilibrium position as a result of inertia.

Explanation:

Just took the test

vlada-n [284]3 years ago
6 0

Complete question is;

An ideal pendulum is often discussed when studying simple harmonic motion.

What are the conditions needed for an ideal pendulum? Check all that apply.

1) Gravitational force acts to pull the pendulum’s mass down.

2) The mass of the rod of the pendulum is evenly distributed along the rod.

3) The pivot on which the pendulum swings is frictionless.

4) The pendulum swings through its equilibrium position as a result of inertia.

5) Tension acts downward on the pendulum’s mass

Answer:

Conditions 2,3 & 4 are the ones that apply

Explanation:

The conditions required for an ideal pendulum are;

- The mass of the rod of the pendulum has to be evenly distributed along the rod.

- Ensure that the pivot on which the pendulum is swinging is frictionless

-The pendulum has to swing through it's equilibrium position as a result of inertia.

Thus,the correct options are 2, 3, 4.

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A man is using a fishing rod to catch fish in figure 1.
ryzh [129]

Answer:

Explanation:

Remark

In general, these 3rd class levers are very inefficient. Because the force distance is smaller than the load distance, you need to pull upward with more force that the weight of the load. So whatever the load is, the force is going to be much greater.

The distances are always measured to the pivot unless you are asked something specific otherwise.

Givens

F = ?

weight = 6N

Force Distance = F*d = 0.5 m

Weight Distance =W*d1 = 2 m

Formula

F*Fd = W*Wd

Solution

F*0.5 = 6 * 2            Divide by 0.5

F = 12/0.5

F = 24 N upwards

5 0
2 years ago
2. A 75 kg runner accelerates from 0.00 m/s to 10.0 m/s in 1.5 seconds.
raketka [301]
A :-) A.a.) Given - u = 0.00 m/s
v = 10.0 m/s
t = 1.5 sec
m = 75 kg
Solution -
a = v - u by t
a = 10 - 0 by 1.5
a = 10 by 1.5
a = 6.6 m/s^2

A.b.) sorry ! I don’t no how to do this question
3 0
3 years ago
Which of the following is not a popular surface for a tennis court?
vovikov84 [41]

The answer is A. wood

because there are three different courts: clay court, grass court, and hard court. wood isn't in there so that would be the answer.

8 0
3 years ago
Two charged particles, with charges q1=q and q2=4q, are located at a distance d= 2.00cm apart on the x axis. A third charged par
Murrr4er [49]

Answer:

X₃₁ = 0.58 m  and  X₃₂ = -1.38 m

Explanation:

For this exercise we use Newton's second law where the force is the Coulomb force

        F₁₃ - F₂₃ = 0

        F₁₃ = F₂₃

Since all charges are of the same sign, forces are repulsive

        F₁₃ = k q₁ q₃ / r₁₃²

        F₂₃ = k q₂ q₃ / r₂₃²

Let's find the distances

         r₁₃ = x₃- 0

         r₂₃ = 2 –x₃

We substitute

      k q q / x₃² = k 4q q / (2-x₃)²

      q² (2 - x₃)² = 4 q² x₃²

        4- 4x₃ + x₃² = 4 x₃²

        5x₃² + 4 x₃ - 4 = 0

We solve the quadratic equation

        x₃ = [-4 ±√(16 - 4 5 (-4)) ] / 2  5

        x₃ = [-4 ± 9.80] 10

       X₃₁ = 0.58 m

       X₃₂ = -1.38 m

For this two distance it is given that the two forces are equal

7 0
3 years ago
Which two options would INCREASE the electric force between two charged particles?
atroni [7]

The electric force between two charged particles can be increased by decreasing the distance between the two particles.

<h3>How to increase electric force between two charged particles.</h3>

The technique of decreasing the separation distance between objects increases the force of attraction or repulsion between the objects. while

increasing the separation distance between objects decreases the force of attraction or repulsion between the objects.

Read more on Electric Force:

brainly.com/question/17692887

#SPJ1

7 0
2 years ago
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