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Serjik [45]
3 years ago
10

An ideal pendulum is often discussed when studying simple harmonic motion. What are the conditions needed for an ideal pendulum?

Check all that apply.
Physics
2 answers:
tamaranim1 [39]3 years ago
8 0

Answer:

Gravitational force acts to pull the pendulum’s mass down.

The pivot on which the pendulum swings is frictionless.

The pendulum swings through its equilibrium position as a result of inertia.

Explanation:

Just took the test

vlada-n [284]3 years ago
6 0

Complete question is;

An ideal pendulum is often discussed when studying simple harmonic motion.

What are the conditions needed for an ideal pendulum? Check all that apply.

1) Gravitational force acts to pull the pendulum’s mass down.

2) The mass of the rod of the pendulum is evenly distributed along the rod.

3) The pivot on which the pendulum swings is frictionless.

4) The pendulum swings through its equilibrium position as a result of inertia.

5) Tension acts downward on the pendulum’s mass

Answer:

Conditions 2,3 & 4 are the ones that apply

Explanation:

The conditions required for an ideal pendulum are;

- The mass of the rod of the pendulum has to be evenly distributed along the rod.

- Ensure that the pivot on which the pendulum is swinging is frictionless

-The pendulum has to swing through it's equilibrium position as a result of inertia.

Thus,the correct options are 2, 3, 4.

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Why is the overall charge of the atom neutral or zero?
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Answer:

B

Explanation:

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What would happen if mass is continually added to a 1.4 solar mass neutron star?
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A very large sheet of insulating material has had an excess of electrons placed on it to a surface charge density of –3.00nC/m2
lys-0071 [83]

Answer: sheet of charge

Explanation:

a )

Since the charge is negative , potential will be negative near it . At a far point potential will be less negative. So potential will virtually increase on going away from the sheet . At infinity it will become almost zero. Electric field will be towards the plate , so potential will decrease towards the plate.

b ) The shape of equi -potential surface will be plane parallel to the sheet of charge because electric field will be perpendicular to the sheet of charge and almost uniform near the sheet of charge.   The equi- potential surface is always perpendicular to electric field.

C ) Electric field which is almost uniform near the sheet of charge is equal t the following

E = σ / ε₀ where  σ is charge density of surface and  ε₀ is permittivity of medium whose value is 8.85 x 10⁻¹²

E = 3 x 10⁻⁹ / 8.85 x 10⁻¹²

= .3389 x 10³

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spacing between 1 V

= 1 / 338.9 m

= 2.95 X 10⁻3 m

= 2.95 mm.

3 0
3 years ago
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