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4 years ago

Can someone please help me with this

Chemistry

2 answers:

Alexxx [7]4 years ago

4 0

The second is the answer.

Gekata [30.6K]4 years ago

3 0

Answer:

b Mass +1 charge 0

Explanation: protons are neutral, so neutrons do not have charge

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Which two factors affect the strength of<br> a metallic bond?

jeyben [28]

Answer: Number of protons and number of valance electrons.

Explanation:

There are three factors which determine metallic bond strength. greater the no of protons, greater will be attraction between nucleus and valance shell electrons and stronger will be metallic bond. greater no of valance electron, greater will be attractions between nucleus and electrons and stronger will be bond.

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4 years ago

What drives the flow of energy in cycling of matter in the atmosphere

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The earths rotation if I’m not mistaken

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3 years ago

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Tresset [83]

Answer:

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3 years ago

Pentaborane−9 (B5H9) is a colorless, highly reactive liquid that will burst into flames when exposed to oxygen. The reaction is

mote1985 [20]

Answer : The heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

Explanation :

Enthalpy change : It is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as $\Delta H^o$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H^o_{rxn}=\sum [n\times \Delta H^o_f(product)]-\sum [n\times \Delta H^o_f(reactant)]$

The equilibrium reaction follows:

$2B_5H_9(l)+12O_2(g)\rightleftharpoons 5B_2O_3(s)+9H_2O(l)$

The equation for the enthalpy change of the above reaction is:

$\Delta H^o_{rxn}=[(n_{(B_2O_3)}\times \Delta H^o_f_{(B_2O_3)})+(n_{(H_2O)}\times \Delta H^o_f_{(H_2O)})]-[(n_{(B_5H_9)}\times \Delta H^o_f_{(B_5H_9)})+(n_{(O_2)}\times \Delta H^o_f_{(O_2)})]$

We are given:

$\Delta H^o_f_{(B_5H_9(l))}=73.2kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(B_2O_3(s))}=-1271.94kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.83kJ/mol$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(5\times -1271.94)+(9\times -285.83)]-[(2\times 73.2)+(12\times 0)]=-9078.57kJ/mol$

Now we have to calculate the heat released per gram of the compound reacted with oxygen.

From the reaction we conclude that,

As, 2 moles of compound released heat = -9078.57 kJ

So, 1 moles of compound released heat = $\frac{-9078.57}{2}=-4539.28kJ$

For per gram of compound:

Molar mass of $B_5H_9$ = 63.12 g/mole

$\Delta H^o_{rxn}=\frac{-4539.28}{63.12}=-71.915kJ/g$

Therefore, the heat released per gram of the compound reacted with oxygen is 71.915 kJ/g

7 0

3 years ago

explain what the discovery of fossil palm tree stumps in Alaska and fossil alligator remains in the Arctic Circle indicates.

Alona [7]

For example, the discovery of fossil palm tree stumps in Alaska and the unearthing of fossil alligator remains in the Arctic Circle suggested that the high latitudes were a tropical landscape 52 million years ago.

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3 years ago

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