Ask question

Ask question

All categories

3 years ago

14

One day the temperature started at -8 degrees Fahrenheit and dropped 14 degrees by the end of the day. What was the temperature

at the end of the day?

1 answer:

sweet [91]3 years ago

3 0

At the end of the day, the temperature was -22°F.

-8-14 = -22

You might be interested in

Solve: x=4+(4x-4)1/2

Damm [24]

Answer:

x = 10

Step-by-step explanation:

x = 4 + (4x-4) ^ (1/2)

First, we rewrite the expression:

x = 4 + (4x-4) ^ (1/2)

x = 2 (2+ (x-1) ^ (1/2))

x = 4 + 2 (x-1) ^ (1/2)

From here we get a solution for x = 10

To check it we substitute x = 10 in the expression:

10 = 4 + 2 (10-1) ^ (1/2)

10 = 4 + 2 (9) ^ (1/2)

10 = 4 + 2 (3)

10 = 4 + 6

10 = 10

Answer:

The solution is:

x = 10

8 0

3 years ago

Read 2 more answers

I couldnt deal with it...

Nikolay [14]

Answer:

oh what subject is this

Step-by-step explanation:

how do u solve it lol

5 0

3 years ago

4 mi = ___ ft <br> answer please!!

Tpy6a [65]

Answer:

21120

Step-by-step explanation:

1 mile = 5280 feet

5280 feet * 4 = 21120

4 0

3 years ago

When adding vegetables to a footlong (30 cm) sandwich, how many ounces or slices of vegetables do you use? select all that apply

MA_775_DIABLO [31]

A footlong sandwich will fit other ingredients besides vegetables, such as 4 slices cheese or 4 strips of beacon, but if we only talk about vegetables, you can 1.5 oz. Lettuce and 1 oz. Onion, 6 slices each; Tomato, cucumber, pickles, pepper, olives, jalapeños.

7 0

4 years ago

A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s

Greeley [361]

Using a system of equations, it is found that:

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

--------------------

The variables of the system are:

x, which is the number of $29 tickets sold.
y, which is the number of $34 tickets sold.

Total of 8,000 seats, all can be sold, thus:

$x + y = 8000 \rightarrow x = 8000 - y$

--------------------

For a profit of $255,000, we have that:

$29x + 34y = 255000$

$29(8000 - y) + 34y = 255000$

$5y = 23000$

$y = \frac{23000}{5}$

$y = 4600$

$x = 8000 - 4600 = 3400$

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.

--------------------

For a profit of $271,000, we have that:

$29x + 34y = 271000$

$29(8000 - y) + 34y = 271000$

$5y = 39000$

$y = \frac{39000}{5}$

$y = 7800$

$x = 8000 - 7800= 200$

For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.

--------------------

For a profit of $235,000, we have that:

$29x + 34y = 235000$

$29(8000 - y) + 34y = 235000$

$5y = 3000$

$y = \frac{3000}{5}$

$y = 600$

$x = 8000 - 600 = 7400$

For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.

A similar problem is given at brainly.com/question/22826010

3 0

3 years ago