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Lelechka [254]
3 years ago
13

Write In Simplifed Form 14(5x-8y)

Mathematics
1 answer:
MrMuchimi3 years ago
4 0
<span>Unary minus: -8
</span><span>Multiple: 5 * (-8) = -40
</span><span>Multiple: 14 * (-40) = -560
The answer is -560

</span>
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1(x-2)= -5.5 solving for x. What's the answer
Lapatulllka [165]

Answer:

x = -3.5

Step-by-step explanation:

1(x-2) = -5.5

x-2 = -5.5

 +2    +2

x = -3.5

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Solve for x: -4(x + 10) - 6 = -3(x - 2
evablogger [386]
-4(x+10)-6=-3(x-2)
-4x-40-6=-3x+6
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-4x-46+46=-3x+6+46
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-4x+3x=-3x+3x+52
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How do I find the area of a rhombus?
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A = pq/2
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3 years ago
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Sample annual salaries (in thousands of dollars) for employees at a company are listed. 42 36 48 51 39 39 42 36 48 33 39 42 45 (
Sonja [21]

Answer:

a) Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

\bar X = 41.538

s = 5.317

b) 44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

\bar X = 43.615

s= 5.583

c) 3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

\bar X= 3.462

s = 0.443

d) As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3.462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

Step-by-step explanation:

For this case we can use the following formulas for the mean and standard deviation:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Part a

Data given: 42 36 48 51 39 39 42 36 48 33 39 42 45

And if we calculate the mean we got:

\bar X = 41.538

s = 5.317

Part b

For this case we know that each value present a 5% of rise so we just need to multiply each value bu 1.05 and we have this new dataset:

44.1, 37.8, 50.4, 53.55, 40.95, 44.1, 37.8, 50.4 ,34.65, 40.95, 44.1, 47.25

And if we calculate the new mean and deviation we got:

\bar X = 43.615

s= 5.583

Part c

The new dataset would be each value divided by 12 so we have:

3.5, 3, 4, 4.25, 3.25, 3.25, 3.5, 3, 4, 2.75, 3.25, 3.5, 3.75

And the new mean and deviation would be:

\bar X= 3.462

s = 0.443

Part d

As we can see, the average of part b is 1.05 times the average of part a (1.05 * 41.538 = 43.615) and the average of part c is equal to the average obtained in part a divided by 12 (41.538 / 12 = 3,462).

And that happens because we create linear transformations for the parts b and c and the linear transformation affects the mean.

And you have the same interpretation for the deviation, it is affected by the linear transformation as the mean.

5 0
3 years ago
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