It is D.
you must multiply the second equation by 3, so that the +3y in the first equation can cancel out the (now) -3y in the second equation.
No guarantee that there will enough hotdogs for the buns, we must find the common multiple between the usual number of hot dogs and buns in each package.
Since we're looking for the smallest common multiple between 8 and 10, we can use the method shown below to compute for the least common multiple.
8 = 2³
10 = 2 x 5
LCM = 2³ x 5 = 40
To purchase 40 hot dogs and buns, you need to buy 5 packages of buns and 4 packages of hot dogs.
Answer:
Hotdog: 4 packages
Buns: 5 packages
Points of intersection are (0,0),(0,8),(10,0),(4,6) plugging them into the equation you get 0,24,10,22. I don't know if you're looking for max value or min value.
I dont see a problem to solve
