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puteri [66]
3 years ago
6

Rhonda has one sheet of paper. She cuts it into thirds and stacks the 3 sheets. If she completes this process a total of 5 times

, how many sheets thick will the resulting stack be? by the way sh only has to complete the process 27 before it reaches the moon.
Mathematics
2 answers:
abruzzese [7]3 years ago
6 0

15 stacks high or 405 if done 27 times

brilliants [131]3 years ago
6 0

Answer:

15 stacks

If she does it for 27 more times it will be

405

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3 equivalent ratios for 5/7
riadik2000 [5.3K]

Answer:

10/14, 15/21, and 20,28

Step-by-step explanation:

You just need to multiply a number on the numerator and the denominator. Remember, whatever you do to the numerator you have to do on your denominator.


8 0
3 years ago
Using the quadratic formula to solve 7x2 – x = 7, what are the values of x?
Kruka [31]
How the quadratic formula works:

For any quadratic equation ax² + bx + c = 0, the solution is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

In the case of our equation 7x² - x = 7, first we need to subtract 7 from each side so that we have 0 on the right.
7x² - x - 7 = 0

Identify the values of a, b, and c.
a = 7, b = -1, and c = -7.

Plug these into our quadratic formula and solve.

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(7)(-7)}}{2(7)}=\boxed{\frac{1\pm\sqrt{197}}{14}

There are two values for x: (1+√197)/14 and (1-√197)/14.
The approximate values for these are 1.073976 and -0.931119.
5 0
3 years ago
Read 2 more answers
Anybody know how to do Special Right Triangles for geometry if so could you explain how to do it.
Lina20 [59]
Step 1: This is a right triangle with two equal sides so it must be a 45°-45°-90° triangle. Step 2: You are given that the both the sides are 3. If the first and second value of the ratio x:x:x√2 is 3 then the length of the third side is 3√2. Answer: The length of the hypotenuse is 3√2 inches.

3 0
2 years ago
A ladder 10 feet long rests against a vertical wall. Initially, the top of the ladder is 8 feet above the ground. If the top of
lora16 [44]

Step-by-step explanation:

Let vertical height of ladder from ground be y and

horizontal distance of the base of the ladder from the wall be x respectively.

Length of the ladder = l (constant) = 10 ft

<u>Using Pythagoras theorem</u>:

{l}^{2}  =  {y}^{2}  +  {x}^{2}

Differentiate both sides w.r.t time

0 = 2y \frac{dy}{dt}  + 2x \frac{dx}{dt}

y \frac{dy}{dt}  + x \frac{dx}{dt}  = 0

<u>We know that</u> (After 1 sec, y = 6 ft and x = 8 ft ; dy/dt = 2 ft/sec)

6\times 2 + 8\frac{dx}{dt}  = 0

\frac{dx}{dt}  =  - 1.5 ft  \: per \: sec

<u>( Ignore - ive sign)</u>

Therefore, bottom of the ladder is sliding away from the wall at a speed of 1.5 ft/sec one second after the ladder starts sliding.

8 0
3 years ago
Can anyone explain to me what to do here? I've been looking at this for like..days and...I still don't get it...
SSSSS [86.1K]

Answer:

I think u have to find the distance.

Each point is given a distinct letter and like wise you have to count the distance between the two points given.

Step-by-step explanation:

Like, 1)distance between A and R when A = -11 and R = -9

their distance is 2 units.

Likewise, 2) RY = 6 units

3) EU = 7 units

4) WD = 5 units

5) EL = 12 units

4 0
3 years ago
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