Salutations!

Insert brackets to make this calculation right 4x2+5-3

The brackets should be inserted outside 2+5. If you add brackets outside teh rest of the numbers the calculation would not make sense.

4 × (2 + 5) - 3

Hope I helped (:

have a great day!

8 0

3 years ago

Please help me answer this.

saul85 [17]

Answer:

it's not 16/,13 ; )

Step-by-step explanation:

5 0

2 years ago

2 2/7× 5 1/6<br><br>what is the answer to this question pls tell me

hodyreva [135]

Answer:

7 19/42

Step 1:

Convert the mixed fractions into improper fraction (Denominator will be same)

2x7+2= 16/7

5x6+1=31/6

Step 2:

LCM of 6 and 7 are 42

Step 3:

217+96/42= 313/42

Step 4:

Covert to mixed fraction so the answer is 7 19/42

7 0

2 years ago

Read 2 more answers

A true/false test has 40 questions. Suppose a passing grade is 30 or more correct answers. Test the claim that a student knows m

Angelina_Jolie [31]

Answer:

z≈3.16

p≈0.001

we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

Step-by-step explanation:

As a result of step 2, we can assume normal distribution for the null hypothesis

z statistic is computed as follows:

z= $\frac{X-M}{\frac{\sqrt{p*(1-p)} }{\sqrt{N} } }$ where

X is the proportion of correct answers in the test ( $\frac{30}{40}$ )
M is the expected proportion of correct answers according to the null hypothesis (0.5)

p is the probability of correct answer (0.5)
N is the total number of questions in the test (40)

z= $\frac{0.75-0.50}{\frac{\sqrt{0.5*(0.5)} }{\sqrt{40} } }$ ≈ 3.16

And corresponding p value for the z-statistic is p≈0.001.

Since p<0.05, we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

7 0

3 years ago