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VMariaS [17]
3 years ago
13

A radioactive isotope of vanadium, V, decays by producing a  particle and gamma ray. The nuclide formed has the atomic number:

A) 22 B) 21 C) 23 D) 24 E) none of these
Chemistry
1 answer:
Slav-nsk [51]3 years ago
6 0

C) 24

Explanation:

When a radioactive isotope of Vanadium, V decays by producing a beta particle and gamma rays, the atomic number will be 24.

 Vanadium is the 23rd element on the periodic table.

It has a mass number of 51.

              atomic number is 23

                                      ⁵¹₂₃V

  A beta particle is symbolized as °₋₁B

   Gamma rays are represented by Y

Now to the equation:

         ⁵¹₂₃V    →    ₐⁿK   +   °₋₁B  +    Y

In a nuclear reaction the mass an atomic number is conserved

   51 = n + 0

            n = 51

   23 = a -1

        a = 24

We can see that the nuclide formed will have an atomic number of 24

learn more:

Transmutation brainly.com/question/3433940

#learnwithBrainly

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Determine the electrical work required to produce one mole of hydrogen in the electrolysis of liquid water at 298°K and 1 atm. T
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Explanation:

The given data is as follows.

          \Delta H = 286 kJ = 286 kJ \times \frac{1000 J}{1 kJ}

                            = 286000 J

 S_{H_{2}O} = 70 J/^{o}K,      S_{H_{2}} = 131 J/^{o}K

 S_{O_{2}} = 205 J/^{o}K

Hence, formula to calculate entropy change of the reaction is as follows.

          \Delta S_{rxn} = \sum \nu_{i}S_{i}_(products) - \sum \nu_{i}S_{i}_(reactants)

                     = [(\frac{1}{2} \times S_{O_{2}}) - (1 \times S_{H_{2}})] - [1 \times S_{H_{2}O}]

                    = [(\frac{1}{2} \times 205) + (1 \times 131)] - [(1 \times 70)]

                    = 163.5 J/K

Therefore, formula to calculate electric work energy required is as follows.

             \Delta G_{rxn} = \Delta H_{rxn} - T \Delta S_{rxn}

                            = 286000 J - (163.5 J/K \times 298 K)

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Thus, we can conclude that the electrical work required for given situation is 237.277 kJ.

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Write the balanced molecular chemical equation for the reaction
Ierofanga [76]

The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

  • For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.

  • According to the question, we are to write a balanced equation for the reaction  in aqueous solution for cesium carbonate and magnesium  nitrate
  • The chemical formula for Cesium carbonate is Cs₂CO₃
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Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

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