Question

A radioactive isotope of vanadium, V, decays by producing a  particle and gamma ray. The nuclide formed has the atomic number: A) 22 B) 21 C) 23 D) 24 E) none of these

Answer 1

C) 24

Explanation:

When a radioactive isotope of Vanadium, V decays by producing a beta particle and gamma rays, the atomic number will be 24.

 Vanadium is the 23rd element on the periodic table.

It has a mass number of 51.

              atomic number is 23

                                      ⁵¹₂₃V

  A beta particle is symbolized as °₋₁B

   Gamma rays are represented by Y

Now to the equation:

         ⁵¹₂₃V    →    ₐⁿK   +   °₋₁B  +    Y

In a nuclear reaction the mass an atomic number is conserved

   51 = n + 0

            n = 51

   23 = a -1

        a = 24

We can see that the nuclide formed will have an atomic number of 24

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