A radioactive isotope of vanadium, V, decays by producing a  particle and gamma ray. The nuclide formed has the atomic number:

Question

2 years ago

13

A) 22 B) 21 C) 23 D) 24 E) none of these

1 answer:

Slav-nsk [51] · Answer 1 · 2022-05-06T00:53:25+03:00

C) 24

Explanation:

When a radioactive isotope of Vanadium, V decays by producing a beta particle and gamma rays, the atomic number will be 24.

Vanadium is the 23rd element on the periodic table.

It has a mass number of 51.

atomic number is 23

⁵¹₂₃V

A beta particle is symbolized as °₋₁B

Gamma rays are represented by Y

Now to the equation:

⁵¹₂₃V → ₐⁿK + °₋₁B + Y

In a nuclear reaction the mass an atomic number is conserved

51 = n + 0

n = 51

23 = a -1

a = 24

We can see that the nuclide formed will have an atomic number of 24

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