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VMariaS [17]
3 years ago
13

A radioactive isotope of vanadium, V, decays by producing a  particle and gamma ray. The nuclide formed has the atomic number:

A) 22 B) 21 C) 23 D) 24 E) none of these
Chemistry
1 answer:
Slav-nsk [51]3 years ago
6 0

C) 24

Explanation:

When a radioactive isotope of Vanadium, V decays by producing a beta particle and gamma rays, the atomic number will be 24.

 Vanadium is the 23rd element on the periodic table.

It has a mass number of 51.

              atomic number is 23

                                      ⁵¹₂₃V

  A beta particle is symbolized as °₋₁B

   Gamma rays are represented by Y

Now to the equation:

         ⁵¹₂₃V    →    ₐⁿK   +   °₋₁B  +    Y

In a nuclear reaction the mass an atomic number is conserved

   51 = n + 0

            n = 51

   23 = a -1

        a = 24

We can see that the nuclide formed will have an atomic number of 24

learn more:

Transmutation brainly.com/question/3433940

#learnwithBrainly

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Cellular Respiration is the process of the release of energy from food. Hence, option B is correct.

<h3>What is cellular respiration?</h3>

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Hence, option B is correct.

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4 0
1 year ago
PLS HELP ASAP <br><br> How does the mass of an object affect its force?
seraphim [82]

Answer:

If mass increases, force increases.

Explanation:

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5 0
3 years ago
An Erlenmeyer flask contains 25.00 mL of 0.10 M HCl. What is the pH of the solution?
max2010maxim [7]
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4 0
4 years ago
Read 2 more answers
What pressure, in atm, would be exerted by 0.023 grams of oxygen (O2) if it occupies 31.6 mL at 91
Vikentia [17]

Answer:  A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

Explanation:

Given : Mass of oxygen = 0.023 g

Volume = 31.6 mL

Convert mL into L as follows.

1 mL = 0.001 L\\31.6 mL = 31.6 mL \times \frac{0.001 L}{1 mL}\\= 0.0316 L

Temperature = 91^{o}C = (91 + 273) K = 364 K

As molar mass of O_2 is 32 g/mol. Hence, the number of moles of O_2 are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.023 g}{32 g/mol}\\= 0.00072 mol

Using the ideal gas equation calculate the pressure exerted by given gas as follows.

PV = nRT

where,

P = pressure

V = volume

n = number of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the value into above formula as follows.

PV = nRT\\P  \times 0.0316 L = 0.00072 mol \times 0.0821 L atm/mol K \times 364 K\\P = \frac{0.00072 mol \times 0.0821 L atm/mol K \times 364 K}{0.0316 L}\\= 0.681 atm

Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen (O_2) if it occupies 31.6 mL at 91^{o}C.

4 0
3 years ago
Explain why the first ionization energy K is less than that of Ca
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Answer:

The first ionization energy for K is less than Ca because Ca has a larger effective nuclear charge.

5 0
3 years ago
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