<u>Answer:</u> The value of 
for the chemical equation is 
<u>Explanation:</u>
For the given chemical equation:
To calculate the for given value of Gibbs free energy, we use the relation:
where,
= Gibbs free energy = 78 kJ/mol = 78000 J/mol (Conversion factor: 1kJ = 1000J)
R = Gas constant = 
T = temperature = 1000 K
= equilibrium constant in terms of partial pressure = ?
Putting values in above equation, we get:
Hence, the value of for the chemical equation is
The chemical weathering process of carbonation removes carbon from the atmosphere. In this process, carbon dioxide in the atmosphere mixes with rainfall to form carbonic acid. This acid then reacts with calcium carbonate or limestone to form calcium bicarbonate. This reaction removes carbon from the atmosphere. Organisms such as corals can remove dissolved carbon from oceans to form their hard rocky structures. Carbon dioxide from the atmosphere is dissolved in ocean water. Overtime they become limestone rock.
Answer:
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Explanation:
Answer:
0 587 mL
Explanation:
First we convert 180 grams of HCl into moles, using its molar mass:
- 180 g ÷ 36.46 g/mol = 4.94 mol HCl
Now we can <u>use the number of moles and the given concentration to calculate the required volume</u>, applying the <em>definition of molarity</em>:
- Molarity = moles / liters
- Liters = Moles / molarity
- 4.94 mol / 8.40 M = 0.588 L
Finally we <u>convert liters into milliliters</u>:
The closest answer is option C, 587 mL.
A gas with a vapor density greater than that of air, would be most effectively displaced out off a vessel by ventilation.
The two following principles determine the type of ventilation: Considering the impact of the contaminant's vapour density and either positive or negative pressure is applied.
Consider a vertical tank that is filled with methane gas. Methane would leak out if we opened the top hatch since its vapour density is far lower than that of air. A second opening could be built at the bottom to greatly increase the process' efficiency.
A faster atmospheric turnover would follow from air being pulled in via the bottom while the methane was vented out the top. The rate of natural ventilation will increase with the difference in vapour density. Numerous gases that require ventilation are either present in fairly low concentrations or have vapor densities close to one.
