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tekilochka [14]
3 years ago
10

At a certain temperature the vapor pressure of pure acetyl bromide is measured to be . Suppose a solution is prepared by mixing

of acetyl bromide and of heptane . Calculate the partial pressure of acetyl bromide vapor above this solution. Round your answer to significant digits. Note for advanced students: you may assume the solution is ideal.
Chemistry
1 answer:
Rudik [331]3 years ago
8 0

Answer:

0.17 atm

Explanation:

Raoult´s law can be applied in solving this problem:

Pa= XaPºa   (a= acetyl bromide in this case)

where Pa = partial pressure acetyl bromide

         Xa = mole fraction of acetyl bromide in the solution

          Pºa=  vapor pressure of pure acetyl bromide = 0.75 atm(given)

Hence we can find the mole fraction of the acetone in the mixture:

Let the number of moles of acetone be a and the number of moles of thiophene be t

Xa = mol of a / ( mol of a + mol of t )        

We now have;

Molar Weight of  a= 112.95 g/mol  

number of moles of a = 51.8 g/mol x 1 mol/122.95 g  =  0.42 moles

Molar Weight of t = 84.14 g/mol  

number of moles of  t = 123 g x  1mol/84.14 g= 1.46 mol

mole fraction of a; Xa = 0.42/ (0.42 + 1.46) = 0.22

Pa = 0.22 x 0.75 atm = 0.17 atm

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mr_godi [17]
Answer:
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Solution:

Step 1) Calculate Molar Mass of SH₂;

Atomic Mass of Sulfur    =  32 g/mol

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                                      --------------------
Molecular Mass of SH₂  =  34 g/mol

Step 2: Calculate mass of one molecule of SH₂ as;

As,

                     Moles  =  # of Molecules / 6.022 × 10²³

Also, Moles  =  Mass / M.Mass So,

                     Mass/M.mass  =  # of Molecules / 6.022 × 10²³

Solving for Mass,

                     Mass  = # of Molecules × M.mass / 6.022 × 10²³

Putting values,

                     Mass  =  (1 Molecule × 34 g.mol⁻¹) ÷ 6.022 × 10²³

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5 0
3 years ago
Read 2 more answers
Consider the halogenation of ethene, where x is a generic halogen: h2c=ch2(g)+x2(g)→h2xc−ch2x(g) you may want to reference (page
KengaRu [80]
Consider the halogenation of ethene is as follows:
CH₂=CH₂(g) + X₂(g) → H₂CX-CH₂X(g)
We can expect that this reaction occurring by breaking of a C=C bond and forming of two C-X bonds.
When bond break it is endothermic and when bond is formed it is exothermic.
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ΔH = + 611 - 678 = -67 kJ

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ΔH = + 611 - 418 = + 193 kJ

Part b)
As we can see that the highest exothermic bond formed is C-F bond so from bond energies we can found that addition of fluoride is the most exothermic reaction
8 0
3 years ago
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Answer:

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Answer:

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