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Gelneren [198K]
3 years ago
8

What happens within clouds and/or within the region between the cloud and Earth that allows for the various forms of precipitati

on?
Chemistry
1 answer:
lesantik [10]3 years ago
5 0
More likely to do whateverrrr they want
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What is the limiting factor in determining the accumulation of siliceous ooze/calcareous ooze, respectively?
zhannawk [14.2K]

Answer:

productivity and water depth

Explanation:

The productivity and the depth of water are both equally important as it directly affects the accumulation of biogenic sediments such as the siliceous ooze and calcareous ooze. In the equator and the coastal upwelling areas, and at the site of divergence of oceans, there occurs a high rate and amount of productivity, and these are considered to be the primary productivity.  

The siliceous oozes are a good indicator of extensively high productivity in comparison to the carbonate oozes. The main reason behind this is that the silica can be easily dissolved in the surface water. On the other hand, the carbonates dissolve at a relatively lower ocean water depth, so there requires a high amount of surface productivity in order to allow these siliceous oozes to reach the ocean bottom.

Thus, the water depth and productivity, both are considered as the limiting factor in determining the accumulation of biogenic oozes.

8 0
3 years ago
In which way are photosynthesis and cellular respiration different?
Lyrx [107]

Answer:

D. Photosynthesis uses carbon dioxide while cellular produces carbon dioxide

3 0
3 years ago
Read 2 more answers
with strong heating calcium carbonate undergoes thermal decomposition how many mole of CaCO3 are there in 50g of calcium carbona
aev [14]
Ca=40
C=12
O=16
1 mole of CaCO3 has 100 grams
So 50 grams is 0.5 mole
6 0
2 years ago
Read 2 more answers
An atom X has atomic number 15,it accepts 3 electrons in other to become stable,determine the,*Number of protons of the atom. *D
Lisa [10]

Answer:

15 protons

8 electrons in valence shell after accepting 3 electrons

Neutral/no charge before accepting 3 electrons

-3 charge after accepting 3 electrons

4 0
2 years ago
Calculate the molarity and normality of 5.7 g of Ca(OH)2 in 450 mL of solution.
Kisachek [45]
  The  molarity   and  normality  of  5.7 g  of  Ca(OH)2   in  450ml  0f    solution  is  calculated  as  follows

molarity  =  moles/volume in  liters
moles  =mass/molar  mass
=  5.7g/74g/mol  =  0.077moles
molarity =  0.077/450  x1000= 0.17M

Normality =  equivalent  point  x molarity
equivalent  point  of Ca(OH)2  is  2   since  it has  two  Hydrogen  atom

normality  is therefore =  0.17  x2 = 0.34 N
7 0
3 years ago
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