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Neporo4naja [7]
4 years ago
14

a student is asked to prepare 75.0 ml of a 130M solution of HF using a 2.000M standard solution. Calculate the volume in mL of 2

.000M HF the student needs to use
Chemistry
1 answer:
Blizzard [7]4 years ago
5 0

Answer:

Volume required from standard solution = 4675 mL

Explanation:

Given data:

Final volume = 75.0 mL

Final molarity = 130 M

Molarity of standard solution = 2.000 M

Volume required from standard solution = ?

Solution:

We use the formula,

C₁V₁ = C₂V₂

here,

C₁ = Molarity of standard solution

V₁ = Volume required from standard solution

C₂ = Final molarity

V₂ = Final volume

Now we will put the values in formula,

C₁V₁ = C₂V₂

2.000 M × V₁ = 130 M × 75.0 mL

V₁  = 9750 M. mL / 2.000 M

V₁  = 4675 mL

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Step 1: List the known quantities and plan the problem.

Known

given: 75.0 g Sn
molar mass of Sn = 118.69 g/mol
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Unknown

mol HF
Use the molar mass of Sn to convert the grams of Sn to moles. Then use the mole ratio to convert from mol Sn to mol HF. This will be done in a single two-step calculation.

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Step 2: Solve.

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75.0 g Sn×
1
mol Sn
118.69
g Sn
×
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mol HF
1
mol Sn
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