Answer:
The answer to your question is: ΔH = -283 kJ/mol, first option
Explanation:
Reaction
CO + O₂ ⇒ CO₂
ΔH = ∑H products - ∑H products
ΔH = -393.5 - (-110.5 + 0)
ΔH = -393.5 + 110.5
ΔH = -283 kJ/mol
Hello!
If the reaction could be made to go faster B. The hill would be shorter.
The "hill" is called Activation Energy. It is the energy of the activated intermediate compound needed to complete the reaction. Catalysts are substances that don't intervene in the reaction which speed up the rate of a given reaction by lowering the Activation Energy giving alternate reaction pathways with lower-energy intermediates. If the reaction could be made to go faster with the use of a catalyst, then the Activation Energy would be lower and the "hill" would be shorter.
Have a nice day!
Heat= mass * change in temperature* specific heat
specific heat=409 J/kg K
multiply the number of each atom with its molecular mass. (see the periodic table)
5*12 + 12*1 = 72 gram per mole.
Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole
