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3 years ago

How much percent of energy presents at one level is available to the next trophic level

1 answer:

4 0

When a herbivore gets eaten by a carnivore, only 10% of energy gets transferred to the next trophic level.

This explains why food chains cannot go on indefinitely.

You might be interested in

What kind of reaction does Iron (III) and copper (II) sulfate solution produce?

ivanzaharov [21]

Answer:

The answer to your question is Single replacement

Explanation:

Types of reaction in Chemistry

Synthesis two or more reactants combine to produce one single product

Decomposition one reactant splits producing two or more products

Single replacement One element replaces a similar one in a compound.

Double replacement Two compounds interchange their cations and anions.

Combustion one compound reacts with oxygen to produce carbon dioxide and water.

Reaction given

Fe⁺² + CuSO₄ ⇒ Cu + FeSO₄

This is a single replacement reaction

4 0

3 years ago

Read 2 more answers

4.33 g of 3-hexanol were obtained from 5.84 g of hex-3-ene. Determine the percentage yield of 3-hexanol. a Determine the moles o

Vilka [71]

Answer: The amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of hex-3-ene = 5.84 g

Molar mass of hex-3-ene = 82.14 g/mol

Putting values in equation 1, we get:

$\text{Moles of hex-3-ene}=\frac{5.84g}{82.14/mol}=0.0711mol$

The chemical equation for the conversion of hex-3-ene to 3-hexanol follows:

$\text{hex-3-ene}+H_2O\xrightarrow []{10\% H_2SO_4} \text{3-hexanol}$

By Stoichiometry of the reaction:

1 mole of hex-3-ene produces 1 mole of 3-hexanol

So, 0.0711 moles of hex-3-ene will produce = $\frac{1}{1}\times 0.0711=0.0711mol$ of 3-hexanol

Now, calculating the mass of 3-hexanol from equation 1, we get:

Molar mass of 3-hexanol = 102.2 g/mol

Moles of 3-hexanol = 0.0711 moles

Putting values in equation 1, we get:

$0.0711mol=\frac{\text{Mass of 3-hexanol}}{102.2g/mol}\\\\\text{Mass of 3-hexanol}=(0.0711mol\times 102.2g/mol)=7.27g$

To calculate the percentage yield of 3-hexanol, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of 3-hexanol = 4.33 g

Theoretical yield of 3-hexanol = 7.27 g

Putting values in above equation, we get:

$\%\text{ yield of 3-hexanol}=\frac{4.33g}{7.27g}\times 100\\\\\% \text{yield of 3-hexanol}=59.56\%$

Hence, the amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %

4 0

3 years ago

Imagine that A and B are cations and X, Y, and Z are anions, and that the following reactions occur:

Gekata [30.6K]

AX(aq)+BY(aq)→no precipitate
AX(aq)+BZ(aq)→precipitate
this two equations imply

AX(aq) is soluble and BY(aq) is insoluble

the answer is
E. BY

5 0

4 years ago

Which molecule has a high specific heat? a) C2H6 b) C2H6O c) H2O

dem82 [27]

H2O is the correct answer :)

4 0

3 years ago

What is the oxidizing agent in galvanic cell?

ipn [44]

The ion in the cathode that gains electrons

7 0

4 years ago