Answer:
Find answers below.
Explanation:
Given the following data;
Voltage = 220V
Current = 15 A
a. To find the power;
Power = current * voltage
Power = 15 * 220
Power = 3300 Watts
b. To find the energy;
Time = 8 hours = 60 * 60 * 8 = 28800 seconds
Energy = power * time
Energy = 3300 * 8
Energy = 26400
Energy = 26.4 Kwh
c. Cost = 13 cents
Cost = 13 * 31 * 26.4
Cost = 106392 cents
E = (1/2)CV²
1 = (1/2)*(2*10⁻⁶)V²
10⁶ = V²
1000 = V
You should charge it to 1000 volts to store 1.0 J of energy.
Answer:
Same magnitude of the 10 nc charge cause the electric field is external.
Explanation:
To do a better explanation, let's go and suppose we have an electric field of, 1300 N/C with a 10 nC charge.
As the system we are talking about is really big, and the charge is small, we can assume always if the charge is sitting right in the same point where the electric field is, then, the electric field would not suffer any kind of alteration in it's value. Therefore, no matter what value of the charge is sitting here, the electric field is independent of the charge, so it would not feel any alteration. However, the force that the charge is feeling would be stronger than in the first case.
F = qE
If charge is doubled, then the force would be bigger in the second case than in the first case, but electric field remain the same value.
a) The mass of the ship is 
b) The ship has a larger momentum than the shell
Explanation:
a)
The momentum of an object is given by:

where
m is the mass of the object
v is its velocity
For the ship in this problem, we have
is the momentum
is the velocity
Solving for m, we find the mass of the ship:

b)
The momentum of the artillery shell is given by

where
m is its mass
v is its velocity
For the shell in this problem,
m = 1100 kg
v = 1200 m/s
Substituting,

So, we see that the ship has a larger momentum.
Learn more about momentum:
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Answer:

Explanation:
The maximum speed of the block occurs when spring has no deformation, that is, there is no elastic potential energy, which can be remarked from appropriate application of the Principle of Energy Conservation:


