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SOVA2 [1]
3 years ago
8

Bandwidth is the: Select one: A. number of frequencies that can be broadcast through a medium. B. number of cycles per second th

at can be sent through a medium. C. difference between the highest and lowest frequencies that can be accommodated on a single channel. D. total number of bytes that can be sent through a medium per second. E. geographical distance spanned by a network.
Physics
1 answer:
natita [175]3 years ago
4 0

Answer:

C. difference between the highest and lowest frequencies that can be accommodated on a single channel.

Explanation:

Bandwidth is the range of the band of frequencies. It is the amount of the data which can be transmitted over a wide range of frequency in the fixed time.

Bandwidth is difference between highest and lowest frequencies in the continuous band of  the frequencies which can be accommodated on the single channel. It is measured in hertz.

<u>Correct answer - C. difference between the highest and lowest frequencies that can be accommodated on a single channel.</u>

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Artemon [7]

Answer:

5 kg

or 11 lbs

Explanation:

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3 years ago
How many moles are in 36g of oxygen?
ololo11 [35]

Answer:

2 moles

Explanation:

2 moles becz

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.: 2 moles of oxygen = 36

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4 years ago
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

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as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
1) The unit of power is
miss Akunina [59]

Answer:

1) the unit of power is A.Watt

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100=50s

divide both sides by 50s

S=2s(A)

4 0
3 years ago
Any help????????????
pashok25 [27]
The answer should be D
3 0
3 years ago
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