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vodomira [7]
4 years ago
10

What is the name of the small early planets, which formed through gravitational attraction reaching sizes of a few miles to even

tually the size of our moon?
Physics
1 answer:
Svetradugi [14.3K]4 years ago
6 0

Answer:

Planetesimals  (Ex, Mercury, Venus , Mars & Earth)

Explanation:

They are known as Planetesimals , They are small in size and have rocky surface. The examples of Planetesimals  are Mercury, Venus Mars and Earth.

They are small early planets , which also has gravitational attraction.

Thanks

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On a part time job you are asked to bring a cylindrical iron rod of density 7800 kg/m^3, length 81.2 cm and diameter 2.75 cm fro
Hitman42 [59]

Answer:

3.76188 kg

36.9040428 N

Yes

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

L = Length of rod = 81.2 cm

d = Diameter of rod = 2.75 cm

r = Radius = \frac{d}{2}=\frac{2.75}{2}=1.375\ cm

A = Area of the cylinder =\pi r^2

v = Volume = L\times A

m = Mass

\rho = Density of rod = 7800 kg/m³

Density

\rho=\dfrac{m}{v}\\\Rightarrow m=\rho\times v\\\Rightarrow m=\rho\times L\times A\\\Rightarrow m=7800\times 0.812\times \pi\times 0.01375^2\\\Rightarrow m=3.76188\ kg

The mass of the rod is 3.76188 kg.

As the the mass of the rod is 3.76188 kg I will be able to carry the rod.

Weight

W=mg\\\Rightarrow W=3.76188\times 9.81\\\Rightarrow W=36.9040428\ N

The weight of the rod is 36.9040428 N

7 0
3 years ago
A power transmission line is hung from metal towers with glass insulators having a resistance of 1.00×109 Ω . What current flows
Hunter-Best [27]

Answer:

The current flows through the insulator is 2 mA.

Explanation:

Given that,

Resistance R=1.00\times10^{9}\ \Omega

Voltage = 200 kV

We need to calculate the current

Using ohm's law

V=IR

I=\dfrac{V}{R}

Where, I = current

V = voltage

R = resistance

Put the value into the formula

I=\dfrac{200\times10^{3}}{1.00\times10^{9}}

I=0.0002\ A

I=2\ mA

Hence, The current flows through the insulator is 2 mA.

5 0
4 years ago
8) A racecar accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the
Vlada [557]

8)Acceleration of the car is 11.17 m/s².

9) Acceleration of skater is 0.57 m/s².

10) The deceleration is 1.8 m/s².

11) The average acceleration of the sprinter is 2 m/s².

12) The velocity of the stroller after 4.75 minutes is 171 m/s.

13) The skier will be moving as 11 m/s speed.

14) 0.56 seconds is required by the rattle snake to reach the speed of 28 m/s from rest.

Answer:

Explanation:

8) Acceleration of the car is determined by finding the ratio of change in velocity to the time taken for the change in velocity. As here the initial velocity is 18.5 m/s and the final velocity is 46.1 m/s, then in 2.47 seconds, the acceleration is

Acceleration = (46.1-18.5)/2.47 = 11.17 m/s².

Acceleration of the car is 11.17 m/s².

9)Similarly, the acceleration of the skater with initial velocity zero to final velocity as 5.7 m/s in 10 seconds is

Acceleration = (5.7-0)/10=0.57 m/s².

So acceleration of skater is 0.57 m/s².

10) In this case, the shuttle bus is stopping so its speed is decreasing from high value to low value. This kind of acceleration related to the decrease in velocity is termed as deceleration as the value of acceleration will be coming as negative.

Acceleration = (0-9)/5=-1.8 m/s².

So the deceleration is 1.8 m/s².

11) Average acceleration of sprinter = (Final velocity-Initial velocity)/Time

Average acceleration = (7.5-5)/1.25=2 m/s².

So the average acceleration of the sprinter is 2 m/s².

12)Since the acceleration of the stroller is given as 0.6 m/s². And the initial velocity is given as zero. So for the time of 4.75 minutes, the velocity will be equal to the final velocity.

As per equations of motion,

v = u +at

As u =0, a = 0.6 m/s² and t = 4.75 ×60 s = 285 s

So v = 0.6×285 = 171 m/s

Thus, the velocity of the stroller after 4.75 minutes is 171 m/s.

13) Similarly, in this case, u = 0, a = 2.2 m/s² and t = 5 s

Then v = u+at=0+(2.2×5)=11 m/s

So the skier will be moving as 11 m/s speed.

14) Here a = 50 m/s² and v = 28 m/s with u = 0 so time taken to reach the speed of 28 m/s is

v = u +at = 0+ (50 t)

28 = 50 t

t = 28/50 = 0.56 s

So 0.56 seconds is required by the rattle snake to reach the speed of 28 m/s from rest.

4 0
4 years ago
the diagram below shows the situation described in the problem. the focal length of the lens is labeled f; the scale on the opti
Artist 52 [7]

Answer:

I have no clue

Explanation:

8 0
2 years ago
An electron moving with a velocity = 5.0 × 107 m/s enters a region of space where perpendicular electric and a magnetic fields a
Cloud [144]

Answer:

magnetic field will allow the electron to go through 2 x 10^{4}  T k

Explanation:

Given data in question

velocity = 5.0 × 10^{7}

electric filed = 10^{4}

To find out

what magnetic field will allow the electron to go through, undeflected

solution

we know if electron move without deflection i.e. net force is zero on electron and we can say both electric and magnetic force equal in magnitude and opposite in directions

so we can also say

F(net) = Fe + Fb i.e. = 0

q V B +  q E = 0

q will be cancel out

10^{4}j + 5e + 7i × B =  0

B = 2 x 10^{4}  T k

3 0
3 years ago
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