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olya-2409 [2.1K]
3 years ago
14

What effect does a catalyst have on a system in equilibrium?

Physics
1 answer:
Jet001 [13]3 years ago
8 0

ANSWER:

What effect does a catalyst have on a system in equilibrium?

The system is unaffected.

~batmans wife dun dun dun....

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A person strikes a ball with a bat. The temperature of the ball increases by 0.06ᵒC. What accounts for the increase?
marusya05 [52]

The increase in the average kinetic energy of the ball causes the increase in the temperature of the ball.

Kinetic energy of a particle is directly proportional to its temperature.

A ball initially at rest acquires kinetic energy when an external force is applied to it. As the person strikes the ball with a bat, the ball gains momentum which increases its kinetic energy of the ball.

Temperature on the other hand, is the measure of the average kinetic energy of a particle. Consequently, as the kinetic energy of the ball increases, the temperature of the ball increases as well.

Thus, we can conclude that the increase in the average kinetic energy of the ball causes the increase in the temperature of the ball.

Learn more here: brainly.com/question/18833622

6 0
2 years ago
Write the equation of motion gover the centre of mass<br><br><br>​
Nataly [62]

Answer:

write the equation of motion go over the centre of mass

Explanation:

the center of mass of a distribution of mass in space (sometimes referred to as the balance point) is the unique point where the weighted relative position of the distributed mass sums to zero. This is the point to which a force may be applied to cause a linear acceleration without an angular acceleration.

6 0
3 years ago
7 the density of the american white oak tree is 752 kilograms per cubic meter. if the trunk of an american white oak tree has a
alexdok [17]

First, we determine the volume of the trunk by finding first the radius from the circumference through the equation,

<span>                                                            C = 2πr</span>

<span>                                                            r = C/2π</span>

Substituting the known values,

<span>                                                            r = 4.5/2π = 0.716 m</span>

Then, we calculate for the volume through the equation,

<span>                                                            V = πr2h</span>

<span>                                                V = π(0.716 m)2(8m) = 12.9 m3</span>

Multiplying the calculated value to the density will give the mass as,

<span>                                                Mass = (12.9 m3)(752 kg/m3) = <span>9699.36 kg</span></span>

3 0
3 years ago
An aquarium open at the top has 30-cm-deep water in it. You shine a laser pointer into the top opening so it is incident on the
Setler [38]

Answer:

You must add 8cm of water to the tank

Explanation:

In order to find how much the height is we will use the Snell Refraction law

.

This law relates the index of refraction of the water (n2), the index of refraction of the air (n1), the incidence angle relative to the vertical (theta1) and the refraction angle relative to the vertical (theta2) by using the next equation:

(n1)*(sin(theta1))=(n2)*(sin(theta2))

Then we will find the refraction angle relative to the vertical this way:

(n1/n2)*(sin(theta1))=sin(theta2)

(1/1.33)*(sin(45))=sin(theta2)

Then, theta2=32.12°

Now that we have this information we can imagine a triangle with a 30cm height and a 32.12° angle. This way we can find how much X is, this X will be the distance between the vertical line and the spot the beam hits the bottom, so we can use some trigonometry to find it, this way:

tan(32.12)=(X/30cm)

X=(tan(32.12))*(30cm)

Then, X=18.8cm, we can approximate it to 19cm

Once we have X we will add 5cm to it which is how much the beam needs to be moved, then the new X will be 24cm

Now, with the new horizontal distance we will find the new vertical distance, let´s call it Y, this way we will know how much water we must add to move the beam, then we will have a triangle with a vertical distance called Y, the same 32.12° angle will be used as we are still working with the air-water interface and a 19cm horizontal distance, then:

tan(32.12)=(24cm/Y)

Y=(24cm/tan(32.12))

Then, Y=38cm

In this case, you must add 8cm of water to the tank to move the beam on the bottom 5cm

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