Answer:
B
Explanation:
This is what the law of conservation of energy is.
The empirical formula of the substance would be 
<h3>Empirical formula calculation</h3>
The constituents of the compound are as follows:
N = 54/201.6 = 26.78% = 26.78/14 = 1.91 moles
H = 15/201.6 = 7.44% = 7.44/1 = 7.44 moles
Cl = 132.6/201.6 = 65.48% = 65.48/35.5 = 1.84 moles
Divide the number of moles by the smallest"
N = 1.91/1.84 = 1
H = 7.44/1.84 = 4
Cl = 1.84/1.84 = 1
Thus, the empirical formula is 
More on empirical formula can be found here: brainly.com/question/14044066
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<h2>
Answer:</h2>
- Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s).
<u>Moles Cu present</u> = 100g Cu x 1 mol Cu/63.55g
= 1.574moles Cu
<u>Mass of Ag produced</u> = 1.574mol Cu x 2mol Ag / 1mol Cu x 107.9g Ag/mol Ag
= 340.g Ag
Answer:
Reducing agents
Oxidized by the reaction
Sorry for late response on the answer.