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4 years ago

6

Consider a transition of the electron in the hydrogen atom from n=5 to n=9. Determine the wavelength of light that is associated

with this transition.

1 answer:

lesantik [10]4 years ago

5 0

Lol i need to answer more and plus n could also = # 4.65

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How did you use QPOE?

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QPOE Files

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3 years ago

Which part of the Periodic Table of the elements is used to identify valence electrons? *

irina1246 [14]

The number of valence electrons of an element can be determined by the periodic table group (vertical column) in which the element is categorized

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3 years ago

What’s a conjugative Bas of OH-

LiRa [457]

Answer:

the answer is O²- hopefully

8 0

3 years ago

Draw a diagram using H+ signs and OH- symbols of a solution that is acidic. Hint: Use the

Dimas [21]

More positive ions shows acidic whereas more negative ions indicates basic solution.

<h3>Which charge show acidic solution?</h3>

That side which has more positive charges is considered as acidic solution while on the other hand, that region where negative charges are present in large number as compared to positive charges is considered as basic or alkaline solution.

So we can conclude that more positive ions shows acidic whereas more negative ions indicates basic solution.

Learn more about charge here: brainly.com/question/25923373

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4 0

2 years ago

When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea

Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0

3 years ago