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Alexus [3.1K]
4 years ago
6

How can we separate the components of a compound?

Chemistry
1 answer:
Alinara [238K]4 years ago
6 0

Answer:

A mixture is a physical combination of substances thus it only requires physical processes to separate. However, a compound is chemically combined and can only be separated by chemical processes. Therefore, it is much harder to separate a compound than a mixture.

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The first statement, the second, as well as the third statement, is not true because these three statements are referring to nuclear fission.
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Imagine your homework assignment involves identifying an unknown pure substance. The valence electrons of the substance's atoms
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The correct answer is (c)  It would have lower ionization energies than K and a lower electronegativity value than K

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Atomic radius decreases --> ionization energy increase---->Electronegativity increases. We can use this flow chart to compare the  IE and EN of the element. As K have lower radii than the unknown element, so the IE and EN of K will be  greater  than the unknown element.

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CuCl2 Determine the name of this compound according to IUPAC nomenclauture. A) copper chloride B) copper (I) chloride C) copper
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Other than rain what kinds of precipitation are there?
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A pure sample of a new chemical compound was analyzed and was found to have the following mass percentages: Al 31.5 %; O 56.1 %;
rjkz [21]

Answer:

The answer to your question is empirical formula   Al₃O₉S

Explanation:

Data

Al = 31.5 %

O = 56.1 %

S = 12.4 %

Process

1.- Look for the atomic masses of the elements

Al = 27 g

O = 16

S = 32

2.- Represent the percentages as grams

Al = 31.5 g

O = 56.1 g

S = 12.4 g

3.- Convert these masses to moles

                               27 g of Al ----------------- 1 mol

                               31.5 g ----------------------  x

                                x = 1.17 moles

                               16 g of O ----------------  1 mol

                               56.1 g of O -------------  x

                                  x = 3.5 mol

                               32 g of S ---------------  1 mol

                               12.4 g of S -------------   x

                                x = 0.39 moles

4.- Divide by the lowest number of moles

Al =   1.17 / 0.39  = 3

O =    3.5 / 0.39 = 8.9 ≈ 9

S  =   0.39 / 0.39 = 1

5.- Write the empirical equation

                                Al₃O₉S

4 0
3 years ago
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