Answer:
5.625 moles of oxygen, O₂.
Explanation:
The balanced equation for the reaction is given below:
4Al + 3O₂ —> 2Al₂O₃
From the balanced equation above,
4 moles of Al reacted with 3 moles of O₂.
Finally, we shall determine the number of mole of O₂ required to react with 7.5 moles of aluminum, Al. This can be obtained as illustrated below:
From the balanced equation above,
4 moles of Al reacted with 3 moles of O₂.
Therefore, 7.5 moles of Al will react with = (7.5 × 3)/4 = 5.625 moles of O₂.
Thus, 5.625 moles of O₂ is needed for the reaction.
The periodic table<span>, and its respective </span>melting<span> and </span>boiling points<span>. ... </span>Chemistry.2<span> The student </span>will <span>investigate and understand that the placement of elements ... </span>Families/groups<span> ... As </span>you<span> analyze </span>your <span>graph, try to </span>answer<span> the </span>following questions<span>: ... </span>period<span>. How </span>would you describe<span> the </span>trend<span> in </span>boiling point<span> as the atomic number ...</span>
Answer:
There are 3 significant figures on this one.
<span>The maximum number of electrons in a single d-subshell is:
10</span>
