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yulyashka [42]
3 years ago
13

Galileo's discovery shows that, to an observer on Earth, Venus has phases just like Earth's moon. How did this observation provi

de support for the heliocentric model of the solar system?
Physics
1 answer:
Pie3 years ago
8 0

<u>Galileo's discovery shows that, to an observer on Earth, Venus has phases just like Earth's moon. This observation provide support for the heliocentric model of the solar system as follows:</u>

  • Galileo noticed the Moon is not flat, but rocky and rugged-just like the Earth did.
  • He used his telescope to observe the Venus phases. Galileo's findings confirmed his confidence in the concept of Copernicus that Earth and remaining planets revolve around the Sun, i.e. Heliocentrism.
  • While most individuals in Galileo's days assumed that the Earth was the center of the universe and that the Sun and planets revolved around it, i.e. geocentrism.
  • The idea of geocentric was generally preferred by the prominent and strong Catholic Church, and when Galileo started writing papers on his belief in a heliocentric with a valid explanation, he was called to Rome to face the inquisition's charges towards him.
  • Thus in early 1616 he was accused of being a heretic, but later he cleared of charges of "heresy" with warning that he should not spread his belief.
  • But he pursued his astronomy research, and was increasingly confident that all planets revolved around the Sun. Therefore  he published a book in 1632 which explained that Copernicus' heliocentric theory was appropriate.
  • Thus after this finally he was charged by "heresy" and sentenced to life imprisonment in 1633, but due to his poor health he lived imprisonment under house arrest and finally died on January 8, 1642.
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Consider the two-body situation at the right. A 300kg crate rests on an inclined plane and is connected by a cable to a 100 kg m
trasher [3.6K]

Answer:

a= 0.578 m/s

T = 1037.8 N

Explanation:

Data

m₁= 300 kg

m₂= 100 kg

inclined plane, θ =  30°

μk = 0.120

Newton's second law to m₁:

We define the x-axis in the direction parallel to the movement of the 300kg (m₁) crate on the ramp and the y-axis in the direction perpendicular to it.

∑F = m₁*a Formula (1)

Forces acting on m₁

W₁: m₁ weight : In vertical direction

N : Normal force : perpendicular to the inclined plane

f : Friction force: parallel to the inclined plane

T:  cable tension : parallel to inclined plane

Calculated of the W₁

W₁=m₁*g

W₁= 300kg* 9.8 m/s² = 2940 N

x-y weight components

W₁x= W₁sin θ =2940 N*sin(30)° =1470 N

W₁y= W₁cos θ =2940 N *cos(30)° =2156.4 N

Calculated of the N

We apply the formula (1)

∑Fy = m*ay    ay = 0

N - W₁y = 0

N = W₁y

N = 2156.4 N

Calculated of the f

f = μk* N= (0.120)*(2156.4 N)

f = 258.77 N

Newton's second law to m₁ in direction  x-axis :

∑Fx = m₁*ax   ,ax  =a

We assume that m₁ descends on the inclined plane and we positively take the direction of movement:

wx-f-T = m*a

wx - f - m*a =T

1470  -258.77 -300*a =T

T= 1211.23-300*a   Equation (1)

Newton's second law to m₂

∑Fy = m₂*ay   ,ay  =a

Forces acting on m₂

W₂: m₂ weight : In vertical direction

T:  cable tension:In vertical direction

Calculated of the W₂

W₂=m₂*g

W₂= 100kg* 9.8 m/s² = 980 N

∑Fy = m₂*a

Because we assume that m₁ descends on the inclined plane, then, m₂ ascends  vertically, we take positive the direction of movement:

T-W₂ = m₂*a

T-980 = 100*a

T = 980 + 100*a Equation (2)

Problem development

Equation (1) =  Equation (2) = T

1211.23-300*a= 980  + 100*a

1211.23- 980 = 100*a + 300*a

231.23 = 400*a

a= 231.23 / 400

a= 0.578 m/s

Because the acceleration tested positive then effectively m₁ descends on the inclined plane and m₂ ascends  vertically.

We replace a= 0.578 m/s in the equatión (2)

T = 980 + 100* (0.578 )

T = 1037.8 N

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Answer:

Check the explanation

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Hey!

NOTE-:

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Using first equation of motion -

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