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1 year ago

15

Briefly explain how a resonance tube works

2 answers:

kicyunya [14]1 year ago

5 0

Answer:

<h3>please mark me as Branliest answer</h3>

Lera25 [3.4K]1 year ago

4 0

Answer:

As the tines of the tuning fork vibrate at their own natural frequency, they created sound waves that impinge upon the opening of the resonance tube. These impinging sound waves produced by the tuning fork force air inside of the resonance tube to vibrate at the same frequency.

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What is meant by sundial???

Fofino [41]

Answer:

Sundial is an instrument showing the time by the shadow of a pointer cast by the sun on to a plate marked with the hours of the day.

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1 year ago

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A thin double convex glass lens with an index of 1.56 while surrounded by air has a 10 cm focal length. If it is placed under wa

bearhunter [10]

Explanation:

Formula which holds true for a leans with radii $R_{1}$ and $R_{2}$ and index refraction n is given as follows.

$\frac{1}{f} = (n - 1) [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

Since, the lens is immersed in liquid with index of refraction $n_{1}$ . Therefore, focal length obeys the following.

$\frac{1}{f_{1}} = \frac{n - n_{1}}{n_{1}} [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

$\frac{1}{f(n - 1)} = [\frac{1}{R_{1}} - \frac{1}{R_{2}}]$

and, $\frac{n_{1}}{f(n - n_{1})} = \frac{1}{R_{1}} - \frac{1}{R_{2}}$

or, $f_{1} = \frac{fn_{1}(n - 1)}{(n - n_{1})}$

$f_{w} = \frac{10 \times 1.33 \times (1.56 - 1)}{(1.56 - 1.33)}$

= 32.4 cm

Using thin lens equation, we will find the focal length as follows.

$\frac{1}{f} = \frac{1}{s_{o}} + \frac{1}{s_{i}}$

Hence, image distance can be calculated as follows.

$\frac{1}{s_{i}} = \frac{1}{f} - \frac{1}{s_{o}} = \frac{s_{o} - f}{fs_{o}}$

$s_{i} = \frac{fs_{o}}{s_{o} - f}$

$s_{i} = \frac{32.4 \times 100}{100 - 32.4}$

= 47.9 cm

Therefore, we can conclude that the focal length of the lens in water is 47.9 cm.

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2 years ago

Which of the following should you always use to protect yourself from hazardous moving parts of power tools and equipment

Andrew [12]

What are the following answers?

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2 years ago

A crime suspect fled the scene when police officers entered the building. How far could he run in 10 minutes if he can run 5 mil

emmainna [20.7K]

(5 mi/hr) x (1hr/60min) x (10min) = 5 x 10 / 60 = <em>5/6 mile</em>

(5/6 mile) x (1,760 yd/mile) = <em>1,466 and 2/3 yards</em>

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2 years ago

If the caffeine concentration in a particular brand of soda is 2.97 mg/oz, 2.97 mg/oz, drinking how many cans of soda would be l

Ray Of Light [21]

Explanation:

The given data is as follows.

Concentration of caffeine = 2.97 mg/oz

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Therefore, the concentration of caffeine in one can is calculated as follows.

= $(12 \times 2.97)$ mg

= 35.64 mg

= $35.64 \times 10^{-3} g$

Since, it is given that lethal dose is 10.0 g. Hence, number of cans are calculated as follows.

No. of cans = $\frac{\text{Lethal dose}}{\text{concentration in one can}}$

= $\frac{10 g}{35.64 \times 10^{-3} g}$

= 280.58

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Thus, we can conclude that 281 cans of soda would be lethal.

5 0

3 years ago