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Igoryamba
4 years ago
15

A tugboat is pushing a barge in to a harbor.The barge is exerting a force of 3000 N against the tugboat.which force would most l

ikely allow the tugboat to move the barge into the harbor​
Physics
1 answer:
julia-pushkina [17]4 years ago
4 0

Answer: The Answer is -4500 N

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A string vibrates at a frequency of 20Hz. what is its period?
Andreas93 [3]
We know, Period = 1/frequency = 1/20 sec.

So, your final answer is 0.05 sec

Hope this helps!
7 0
3 years ago
A wave of infrared light has a speed of 6 m/s and a wavelength of 12 m. What is the frequency of this wave?
givi [52]
I'll be happy to solve the problem using the information that
you gave in the question, but I have to tell you that this wave
is not infrared light.

If it was a wave of infrared, then its speed would be close
to 300,000,000 m/s, not 6 m/s, and its wavelength would be
less than 0.001 meter, not 12 meters.

For the wave you described . . .

             Frequency  =  (speed)  /  (wavelength)

                                 =  (6 m/s)  /  (12 m)

                                 =      0.5 / sec

                                 =      0.5 Hz .  

(If it were an infrared wave, then its frequency would be
greater than 300,000,000,000 Hz.)
5 0
3 years ago
Read 2 more answers
Suppose a rocket is traveling through space and moving at a speed close to the speed of light. Three minutes pass on the rocket
Sedbober [7]

Answer:

B

Explanation:

on edge2020

4 0
3 years ago
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2. A person began running due east and covered 15 kilometers in 2.0 hours. What is the average velocity of the person?
Angelina_Jolie [31]

Answer:

7.5 km/h (2.1 m/s) due east

Explanation:

The average velocity of the person is given by:

v=\frac{d}{t}

where

d is the displacement

t is the time taken

In this problem,

d = 15 km is the displacement

t = 2.0 h is the time elapsed

so the average velocity is

v=\frac{15 km}{2.0 h}=7.5 km/h

and the direction is the same as the displacement (east).

We can also convert the velocity into SI units (m/s). We have:

d = 15 km = 15,000 m

t = 2.0 h * 3600 s/h = 7200 s

v=\frac{15,000 m}{7200 s}=2.1 m/s

4 0
3 years ago
Read 2 more answers
When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g
Olegator [25]

Answer:

Your question was incomplete so here is the complete question and answer.

Q. When exercising in the heat, which of the following hydration strategies is best for temperature regulation during an event (e.g., 10K race)

a) plain water

b) 5-7 percent glucose solution

c) Glucose polymer solution of 6-8 percent

d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.

Ans. d) There appears to be no difference among these different forms of hydration techniques relative to temperature regulation.

Explanation:

Temperature Regulation is an important phenomenon for the person exposed to extreme hot conditions or weather. Exercising in hot conditions increase the body temperature. Greater and intense exercise, greater the production of heat. Then the heat dissipation takes place in the form of excessive sweating which results in dehydration. That was just the brief overview of temperature regulation. Above mentioned techniques are equally good hydration techniques so there is no difference at all. You can have a plain water or glucose solutions of above mentioned percentages.

3 0
3 years ago
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