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Natalka [10]
3 years ago
9

Approximate the solution to the system of equations.

Mathematics
1 answer:
Ann [662]3 years ago
8 0

Answer:

a) at x=0.5  y=2  and at x=1  y=2 this similarity in values shows that the solution for x is between 0.5 and 1

c) The x  solution will be between  x=0.0 and x=0.7 .

There is a similarity in values of y at x=0.6, y=2.4 and at x=0.7 , y=2.4

d) For x= (0.6+0.7)/2 = 1.3/2 =0.65

   For y= (2.4+2.3)/2 =4.7/2=2.35

  Approximate solution is (0.65, 2.35)

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What is the base if the height is 6ft and the area is 14 ft on a triangle ​
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a = area

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The scores on the LSAT are approximately normal with mean of 150.7 and standard deviation of 10.2. (Source: www.lsat.org.) Queen
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a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the  scores on the LSAT of a population, and for this case we know the distribution for X is given by:

X \sim N(150.7,10.2)  

Where \mu=150.7 and \sigma=10.2

We want to find a value a, such that we satisfy this condition:

P(X>a)=0.65   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.35 of the area on the left and 0.65 of the area on the right it's z=-0.385. On this case P(Z<-0.385)=0.35 and P(Z>-0.385)=0.65

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

Z=-0.385

And if we solve for a we got

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

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