it means basically the same thing but can be used in different context. like if someone says, "lets diffuse the situation." it means lets separate it and find out what's going on with it. Like if you don't understand a sentence when you were younger your teacher would tell you to break down the sentence, and try to use context clues. What you are doing is diffusing the sentence so that your not looking at it as one big confusing sentence, your "breaking it down" and that helps you a lot. I hope I helped you, if not let me know and I can diffuse the topic a little more to make it more approachable and easy to understand. :)
Answer:
Phosphorus trichloride, PCl₃ undergoes change in bonding and molecular force of attraction, causing it to be liquid at room temperature.
Explanation:
Unlike other chlorides of Period 3 elements, Phosphorus trichloride, PCl₃ changes the structure of its molecular bonding from ionic to covalent bonds as it transitions to fluids (liquids or gases). The PCl₃ molecule also has the weak Van der Waals dispersion and dipole-dipole attraction, making it a fuming liquid at room temperature, with no electrical conductivity.
You have to use the equation PV=nRT.
P=pressure (in this case 1.89x10^3 kPa which equals 18.35677 atm)
1V=volume (in this case 685L)
n=moles (in this case the unknown)
R=gas constant (0.08206 (L atm)/(mol K))
T=temperature (in this case 621 K)
with the given information you can rewrite the ideal gas law equation as n=PV/RT.
n=(18.35677atm x 685L)/(0.08206atmL/molK x 621K)
n=246.8 moles
<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.
<u>Explanation:</u>
For the given nuclear reaction:

We are given:
Mass of
= 39.963998 u
Mass of
= 39.962591 u
To calculate the mass defect, we use the equation:

Putting values in above equation, we get:

To calculate the energy released, we use the equation:

(Conversion factor:
)

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.
Answer:
Pro exercise con suffication
Explanation:
...