The change in temperature had the greatest effect at changing the volume of the balloon.
<h3>What are the gas laws?</h3>
The gas laws are used to describe the parameters that has to do with gases.
Given that;
P1 = 98.5 kPa
T1 = 18oC or 291 K
V1 = 74.0 dm3
P2 = 7.0 kPa
V2 = ?
T2 = 18oC or 291 K
P1V1/T1 = P2V2/T2
P1V1T2 =P2V2T1
V2= P1V1T2/P2T1
V2 = 98.5 kPa * 74.0 dm3 * 291 K/ 7.0 kPa * 291 K
V2 = 1041.3 dm3
When;
V1 = 1041.3 dm3
T1 = 291 K
V2 = ?
T2 = 80oC or 353 K
V1/T1 = V2/T2
V1T2 = V2T1
V2 = V1T2/T1
V2 = 1041.3 dm3 * 353 K/291 K
V2 = 1263 dm3
The change in temperature had the greatest effect at changing the volume of the balloon.
Given that
V1 = 100 cm^3
T1 = 273 K
P1 = 1.01 * 10^5 Pa
V2 = ?
P2 = 3.00 x 10^-4 Pa
T2 = -180oC or 255 K
V2= P1V1T2/P2T1
V2 = 1.01 * 10^5 Pa * 100 cm^3 * 255 K / 3.00 x 10^-4 Pa * 273 K
V2 = 3.14 * 10^10 cm^3
Learn more about gas laws:brainly.com/question/12669509
#SPJ1
Hey there!
Magnesium oxalate: MgC₂O₄
Mg: 1 x 24.305 = 24.305
C: 2 x 12.01 = 24.02
O: 4 x 16 = 64
----------------------------------
112.325 g/mol
The molar mass of magnesium oxalate is 112.325 g/mol.
Hope this helps!
Answer:
1.204 g/mL
Explanation:
Step 1: Given data
Mass of the unknown liquid (m): 36.185 g
Volume of the unknown liquid (V): 30.05 mL
Step 2: Calculate the density of the unknown liquid
The density is an intrinsic property, which can help to identify an unknown substance. It is equal to the mass divided by the volume.
ρ = m / V
ρ = 36.185 g / 30.05 mL
ρ = 1.204 g/mL