Draw and label a figure that has 4 points, 2 rays and 1 right angle

Tawanna is asked to find the GCF of each term in the expression 2 a b + 8 b. Her work is shown below.

deff fn [24]

Answer:

Tawanna should have used each common factor once.

Step-by-step explanation:

Tawanna is asked to find the GCF of each term in the expression 2 a b + 8 b.

Factors of 2ab: 1, 2, a, and b

Factors of 8b: 1, 2, 4, 8, and b

GCF: (1) (1) (2) (2) (b) (b)

GCF = Greatest common factor

She has calculated the GCF incorrectly as she should use each common factor once only. But she has taken all the common factors twice which is wrong.

Hence, the error in Tawanna’s solution is that "Tawanna should have used each common factor once.". Hence, the correct option is (c).

8 0

3 years ago

Read 2 more answers

Complete the table. then describe a pattern in the decimal forms o the fractions.

DerKrebs [107]

It's going down by five but I'm sure on the last one..but to help add a zero like if it 0.5 it would be 0.50 that should help.

3 0

3 years ago

In ΔABC, where ∠C is a right angle, cos A=√21/5. What is sin B?

Stolb23 [73]

Answer:

A

Step-by-step explanation:

7 0

4 years ago

Given: 3j+k/2=15-4k; Prove j=10-3k<br><br> And Given 5x-2y=x+14; Prove y=2x-7

baherus [9]

Answer:

I LIKE TRAINS

Step-by-step explanation:

TRAINS 34

4 0

3 years ago

Which of the following is true of the location of an angle, Theta, whose tangent value is Negative StartFraction StartRoot 3 End

Anuta_ua [19.1K]

The value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Given to us

$tan \theta =-\dfrac{\sqrt{3}}{3}$

<h3>What is the value of $tan \theta =\dfrac{\sqrt{3}}{3}$ ?</h3>

To know the value $tan \theta =\dfrac{\sqrt{3}}{3}$ we will simplify the given expression,

$tan \theta =\dfrac{\sqrt{3}}{3}\\\\\\tan \theta =\dfrac{1}{\sqrt{3}}\\\\tan \theta =30^o$

Hence, the value of theta is 30°.

<h3>Finding the location of the - tan30°?</h3>

To know that the location of the -tan30°,

$tan30^o = -\dfrac{sin30^o}{cos30^o}$

As the value is negative, therefore, there can be two cases,

Case I: when the value of Sin30° is negative,

Case II: when the value of cos30° is negative.

Case I: when the value of Sin30° is negative,

If the value of Sin30° is negative, while the value of cos30° is positive, the θ will lie in the fourth quadrant.

Case II: when the value of Cos30° is negative,

If the value of Cos30° is negative, while the value of Sin30° is positive, the θ will lie in the second quadrant.

Hence, the value of theta has a 30-degree reference angle and is located in Quadrant II or IV.

Learn more about Quadrants:

brainly.com/question/350459

5 0

3 years ago