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podryga [215]
3 years ago
5

Find the solutions to the equation below. Check all that apply. 4x2 + 4x + 1 = 0

Mathematics
1 answer:
Verizon [17]3 years ago
4 0

Answer:

The solution for the given polynomial 4x^2 + 4x+ 1 = 0 is x  = (\frac{-1}{2})

Step-by-step explanation:

Here, the given quadratic equation is : 4x^2 + 4x+ 1 = 0

Now, here solving the given equation by SPLITTING THE MIDDLE TERM:

4x^2 + 4x+ 1 = 0  = 4x^2 + 2x+ 2x +  1 = 0\\\implies 2x( 2x + 1) + 1(2x + 1) = 0\\\implies (2x +1)(2x +1)  = 0\\

⇒ either (2x+1) = 0, or ( 2x + 1) = 0

⇒ x = -1/2 or x  = -1/2

Here, in both the cases, the value of x is equal i.e x  =  -1/2

So, the given function has TWO IDENTICAL ROOTS.

Hence the solution for the given polynomial 4x^2 + 4x+ 1 = 0 is x  = (\frac{-1}{2})

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Which equation shows the relationship between the volume, (V) of the prism and its height (h)?
denis-greek [22]

Answer:

h = V/lw

Step-by-step explanation:

We know the formula for the volume of a rectangular prism is V = lwh. We need to use this equation and solve for h by dividing lw on both sides.

V = lwh

V/lw = h

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3 years ago
M-3x=2x+p<br> Solve for x
abruzzese [7]
X=m/5-p/5 i tried my best to answer this problem

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3 years ago
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A student saves $3 dollars on August 1, $5 on August 2, $7 on August 3, and so on. How much will she save in August 20 ?
Delvig [45]
Here is your answer

Money saved on each successive day is-

$3, &5, $7....

Clearly it forms an AP,

where

a1= 3

common difference, d= 2

n=20

So,

using formula

Tn= a1+(n-1)d

T20= 3+(20-1)2

= 3+ 19×2

= 3+ 38

=41

So, money saved on August 20= $41

Sum of money saved upto August 20 =
n/2 (a1+T20)
= 20/2 (3+41)
= 10× 44
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5 0
3 years ago
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The relationship between V, the value of his car, in dollars, and t, the elapsed time, in years, since he
Sergio [31]

Answer:

t = -24*log(2/3)

Step-by-step explanation:

The expression is:

V = 22,500*10^(-t/12)

Replacing with V = 10,000 and isolating t, we get:

10,000 = 22,500*10^(-t/12)

10,000/22,500 = 10^(-t/12)

4/9 = 10^(-t/12)

(2/3)² = 10^(-t/12)

2*log(2/3) = -t/12

-12*2*log(2/3) = t

t = -24*log(2/3)

6 0
2 years ago
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Compare the two graphs and explain the transformation that was applied to f(x) in order to look exactly like the graph of g(x).
Neporo4naja [7]

The two graphs are represented below.

Answer and Step-by-step explanation: One graph can "transform" into another through changes in the function.

There are 3 ways to change a function:

  1. <u>Shifting</u>: it adds or subtracts a constant to one of the coordinates, thus changing the graph's location. When the <em><u>y-coordinate</u></em> is<em> </em>added or subtract and the x-coordinate is unchanged, there is a <em><u>vertical</u></em> <u><em>shift</em></u>. If it is the <em><u>x-coordinate</u></em> which changes and y-coordinate is kept the same, the shift is a <em><u>horizontal</u></em> <u><em>shift</em></u>;
  2. <u>Scaling</u>: it multiplies or divides one of the coordinates by a constant, thus changing position and appearance of the graph. If the <em>y-coordinate</em> is multiplied or divided by a constant but x-coordinate is the same, it is a <em>vertical scaling</em>. If the <em>x-coordinate</em> is changed by a constant and y-coordinate is not, it is a <em>horizontal</em> <em>scaling</em>;
  3. <u>Reflecting</u>: it's a special case of scaling, where you can multiply a coordinate per its opposite one;

Now, the points for f(x) are:

(-5,0)  (0,6)  (5,-4)  (8,0)

And the points for g(x) are:

(-5,-3)  (0,-9)   (5,1)   (8,-3)

Comparing points:

(-5,0) → (-5,-3)

(0,6) → (0,-9)

(5,-4) → (5,1)

(8,0) → (8,-3)

It can be noted that x-coordinate is kept the same; only y-coordinate is changing so we have a vertical change. Observing the points:

(-5,0-3) → (-5,-3)

(0,6-15) → (0,-9)

(5,-4+5) → (5,1)

(8,0-3) → (8,-3)

Then, the vertical change is a <u>Vertical</u> <u>Shift</u>.

Another observation is that y-coordinate of f(x) is the opposite of g(x). for example: At the second point, y-coordinate of f(x) is 6, while of g(x) is -9. So, this transformation is also a <u>Reflection</u>.

<u>Range</u> <u>of</u> <u>a</u> <u>function</u> is all the values y can assume after substituting the x-values.

<u>Domain</u> <u>of</u> <u>a</u> <u>function</u> is all the values x can assume.

Reflection doesn't change range nor domain of a function. However, vertical or horizontal translations do.

Any vertical translation will change the range of a function and keep domain intact.

Then, for f(x) and g(x):

graph            translation            domain      range

f(x)                       none                 [-5,8]          [-4,6]

g(x)                vertical shift           [-5,8]          [-9,1]

<u>In conclusion, this transformation (or translation) will affect the range of g(x)</u>

5 0
2 years ago
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