Question

Find the solutions to the equation below. Check all that apply. 4x2 + 4x + 1 = 0

Answer 1

Answer:

The solution for the given polynomial $4x^2 + 4x+ 1 = 0$ is $x = (\frac{-1}{2})$

Step-by-step explanation:

Here, the given quadratic equation is : $4x^2 + 4x+ 1 = 0$

Now, here solving the given equation by SPLITTING THE MIDDLE TERM:

$4x^2 + 4x+ 1 = 0 = 4x^2 + 2x+ 2x + 1 = 0\\\implies 2x( 2x + 1) + 1(2x + 1) = 0\\\implies (2x +1)(2x +1) = 0$

⇒ either (2x+1) = 0, or ( 2x + 1) = 0

⇒ x = -1/2 or x  = -1/2

Here, in both the cases, the value of x is equal i.e x  =  -1/2

So, the given function has TWO IDENTICAL ROOTS.

Hence the solution for the given polynomial $4x^2 + 4x+ 1 = 0$ is $x = (\frac{-1}{2})$