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podryga [215]
3 years ago
5

Find the solutions to the equation below. Check all that apply. 4x2 + 4x + 1 = 0

Mathematics
1 answer:
Verizon [17]3 years ago
4 0

Answer:

The solution for the given polynomial 4x^2 + 4x+ 1 = 0 is x  = (\frac{-1}{2})

Step-by-step explanation:

Here, the given quadratic equation is : 4x^2 + 4x+ 1 = 0

Now, here solving the given equation by SPLITTING THE MIDDLE TERM:

4x^2 + 4x+ 1 = 0  = 4x^2 + 2x+ 2x +  1 = 0\\\implies 2x( 2x + 1) + 1(2x + 1) = 0\\\implies (2x +1)(2x +1)  = 0\\

⇒ either (2x+1) = 0, or ( 2x + 1) = 0

⇒ x = -1/2 or x  = -1/2

Here, in both the cases, the value of x is equal i.e x  =  -1/2

So, the given function has TWO IDENTICAL ROOTS.

Hence the solution for the given polynomial 4x^2 + 4x+ 1 = 0 is x  = (\frac{-1}{2})

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