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jek_recluse [69]
3 years ago
13

Ahsoka pulls a wounded soldier (mass 64 kg) across the ground with a force 18 Newtons. If they have an acceleration of 1.5 m/s2

Physics
2 answers:
Mekhanik [1.2K]3 years ago
7 0

Hello!

Let's applicate formula:

F - Ff = ma

How we dont know friction force, we descompose it in:

F - (μ * N) = ma

Now, lets replace (N = Is the normal force, or weight in this case):

18 N - (μ * (64 kg * 9,81 m/s²) = 64 kg * 1,5 m/s²

First, lets resolve parenthesis:

18 N - (μ * 627,84 N) = 96 N

The force happens to subtract:

- (μ * 627,84 N = 96 N - 18 N

-μ = 78 N / 627,84 N

-μ = 0,124

The value of <u>μk = 0,124</u>

Kryger [21]3 years ago
4 0

Answer:

0.124

Explanation:

18-(9.81*64)*k=64*1.5

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For what absolute value of the phase angle does a source deliver 71 % of the maximum possible power to an RLC circuit
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Answer: the absolute value of the phase angle is 28°

Explanation:

taking a look at expression for the instantaneous electric power in an AC circuit;

P = VI -------let this be equation 1

p is power, v is voltage and I is current;

for maximum power

P_max = V_rms × I_rms --------let this be equ 2

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Also for average electric power in an AC circuit

P_avg = V_rms × I_rms × cos²∅ -------let this be equ 3

where P_avg is the average power and cos∅ is the power factor

now from equation 2;  P_max = V_rms × I_rms

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we now have

P_avg = P_max × cos²∅

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expression for the given value of the average power is

P_avg = P_max × 75%

p_avg = P_max.78/100

for the expression of the average electricity in an AC circuit

P_max.78/100 = P_max × cos²∅

78/100 = cos²∅

to get the absolute value of phase angle

∅ = cos⁻¹ ( √(78/100))

∅ =  cos⁻¹ ( 0.8832)

∅ = 27.969 ≈ 28°

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8 0
3 years ago
A 300 kg car initially travels with a velocity of 20 m/s to the right. A net force F acts on the car for 5 s, which causes the v
hram777 [196]

Answer:

<em>600N.</em>

Explanation:

From the question, we are to calculate the net force acting on the car.

According to Newton's second law of motion:

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m is the mass of the car

a is the acceleration = change in velocity/Time

a = v-u/t

F = m(v-u)/t

v is the final velocity = 30m/s

u is the initial velocity = 20m/s

t is the time = 5secs

m = 300kg

Get the net force:

Recall that: F = m(v-u)/t

F  = 300(30-20)/5

F = 60(30-20)

F = 60(10)

<em>F = 600N</em>

<em>Hence the net force acting on the car is 600N.</em>

<em></em>

<em></em>

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What is average velocity?
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Suppose you wish to fabricate a uniform wire out of 1.10 g of copper. If the wire is to have a resistance R = 0.390 Ω, and if al
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lA = 1.233*10^{-7} m^3 (1)

We know that,

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\frac{l}{A} = 2.2941*10^7 m^{-1} (2)

Multiplying equation we have

l^2 = (1.233*10^{-7})( 2.2941*10^7)

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Distinguish between basic and derived units
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Answer:

Base units are defined units based on specific objects or events in the physical world. Derived units are defined by combining base units.

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