All categories

3 years ago

Ahsoka pulls a wounded soldier (mass 64 kg) across the ground with a force 18 Newtons. If they have an acceleration of 1.5 m/s2

Physics

2 answers:

Mekhanik [1.2K]3 years ago

7 0

Hello!

Let's applicate formula:

F - Ff = ma

How we dont know friction force, we descompose it in:

F - (μ * N) = ma

Now, lets replace (N = Is the normal force, or weight in this case):

18 N - (μ * (64 kg * 9,81 m/s²) = 64 kg * 1,5 m/s²

First, lets resolve parenthesis:

18 N - (μ * 627,84 N) = 96 N

The force happens to subtract:

- (μ * 627,84 N = 96 N - 18 N

-μ = 78 N / 627,84 N

-μ = 0,124

The value of <u>μk = 0,124</u>

Kryger [21]3 years ago

4 0

Answer:

0.124

Explanation:

18-(9.81*64)*k=64*1.5

You might be interested in

An ice cube sitting on a piece of wood would melt:

Aleksandr [31]

The answer would be slowly

3 0

3 years ago

Read 2 more answers

In the flow past a compression corner, the upstream Mach number and pressure are 3.5 and 1 atm, respectively. Downstream of the

yulyashka [42]

Answer:

$\theta=23.7^{\circ}$

Explanation:

The ratio of pressure 2 to 1 us 5.48/1= 5.48 rounded off as 5.5.

Referring to table A.2 of modern compressible flow then $M_{\beta_1}=2.2$

Also

$M_{\beta_1}=M_1 sin \beta$ and making $sin\beta$ the subject of the formula then

$sin\beta=\frac {2.2}{3.5}\\\beta=38.94^{\circ}$

Making reference to $\theta-\beta-M$ diagram then

$\theta=23.7^{\circ}$

4 0

3 years ago

When designing an experiment how do you choose a system to investigate

Nana76 [90]

You pick a system for which no control sample exists, so that no one can show that the alleged causal relationships you assert do not, in fact, lead to the phenomenon you claim to have observed.

4 0

3 years ago

A capacitor with an initial potential difference of 185 V is discharged through a resistor when a switch between them is closed

GrogVix [38]

Answer:

a. $\tau = 2.1161 s$

b. $V(18.8 \ s) = 0.0256 \ V$

Explanation:

The equation for the voltage V of discharging capacitor in an RC circuit at time t is:

$V(t) = V_0 e^{(- \frac{t}{\tau}) }$

where $V_0$ is the initial voltage, and $\tau$ is the time constant.

For our problem, we know

$V_0 = 185 \ V$

and

$V(10 \ s) = V_0 e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V$

$185 \ V \ e^{(- \frac{10 \ s}{\tau}) } = 1.64 \ V$

$e^{(- \frac{10 \ s}{\tau}) } = \frac{1.64 \ V}{ 185 \ V }$

$ln (e^{(- \frac{10 \ s}{\tau}) } ) = ln (\frac{1.64 \ V}{ 185 \ V })$

$- \frac{10 \ s}{\tau} = ln (\frac{1.64 \ V}{ 185 \ V })$

$\tau = \frac{-10 \s}{ln (\frac{1.64 \ V}{ 185 \ V }) }$

This gives us

$\tau = 2.1161 s$

and this is the time constant.

At t = 18.8 s we got:

$V(18.8 \ s) = 185 \ V \ e^{(- \frac{18.8 \ s}{2.1161 s}) }$

$V(18.8 \ s) = 0.0256 \ V$

4 0

3 years ago

A bicyclist steadily speeds up from rest to 11.0m/s during a 5.50s time interval. Determine all unknowns and answer the followin

Marina86 [1]

Explanation:

acceleration is 2 m/s^2

v-u/t

distance travelled is 30.25 meter

(v^2-u^2)/2a

11*11/2*2

121/4

30.25 m

5 0

3 years ago