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Bess [88]
2 years ago
7

A shopper is pushing a cart down a grocery store aisle. Starting from rest, the shopper applies a constant force to the cart for

4.0 s. From t = 4s until t = 4 s until t = 8 s, the shopper applies just enough force to balance the friction on the cart. Finally, the shopper applies a constant force to slow the cart until it comes to rest att = 12 s. The resulting position-time graph is shown below. What is the average acceleration of the shopping cart during its 12s motion?​

Physics
2 answers:
Taya2010 [7]2 years ago
7 0

Answer:0 m/s2

Explanation: Cus i said so.

inysia [295]2 years ago
3 0

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

A shopper is pushing a cart down a grocery store aisle. The movement of the cart is:

  • It starts from rest.
  • From t = 0 s to t = 4.0 s it is accelerated with a constant force.
  • From t = 4 s to t = 8.0 s it receives just enough force to balance the friction on the cart.
  • From t = 8 s to t = 12 s it is decelerated until it comes to rest.

All in all, at the initial time (t = 0 s), the velocity is 0 m/s (rest) and at the final time (t = 12 s) the velocity is 0 m/s as well (rest). The average acceleration in that period is:

a = \frac{v_{12}-v__o}{t_{12}-t_0} = \frac{0m/m-0m/s}{12s-0s}  = 0 m/s^{2}

A shopping cart that starts from rest, is accelerated for 4 s, moves at constant velocity for 4 s, and is decelerated for 4s until returning to rest, has an average acceleration of 0 m/s².

Learn more: brainly.com/question/16274121

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If you walk at an average speed of 5 km/h for 30 minutes, how
Inessa05 [86]

The distance that would be accumulated during the journey is 2.5 meters

The parameters given in the question are  written below;

average speed= 5 km/hr

time = 30 minutes

convert 30 minutes to hours

= 30/60

= 0.5 hours

Distance-= speed × time

= 5 × 0.5

= 2.5 meters

Hence the distance of the entire journey is 2.5 meters

Please see the link below for more information

brainly.com/question/24268730?referrer=searchResults

3 0
3 years ago
Which statement is true for a sound wave entering an area of warmer air
Reika [66]
That waves travel faster than the wave lenght!
8 0
3 years ago
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Infrared waves from the sun are what make our skin feel warm on a sunny day. If an infrared wave has a frequency of 3.0 x 1012 H
djyliett [7]

Answer:

The wavelength of the infrared wave is <u>0.0001 m</u>.

Explanation:

Given:

Frequency of an infrared wave is, f=3.0\times 10^{12}\ Hz

We know that, infrared waves are electromagnetic waves. All electromagnetic waves travel with the same speed and their magnitude is equal to the speed of light in air.

So, speed of infrared waves coming from the Sun travels with the speed of light and thus its magnitude is given as:

v=c=3.0\times 10^8\ m/s

Where, 'v' is the speed of infrared waves and 'c' is the speed of light.

Now, we have a formula for the speed of any wave and is given as:

v=f\lambda

Where, \lambda \to \textrm{Wavelength of infrared wave}

Now, rewriting the above formula in terms of wavelength, \lambda, we get:

\lambda=\dfrac{v}{f}

Now, plug in 3.0\times 10^8 for 'v', 3.0\times 10^{12} for 'f' and solve for  \lambda. This gives,

\lambda=\frac{3.0\times 10^8}{3.0\times 10^{12}}\\\\\lambda=0.0001\ m

Therefore, the wavelength of the infrared wave is 0.0001 m.

5 0
3 years ago
Explain how electric currents flow only in closed circuits​
Fed [463]

Answer:

The wires are connected to both terminals of the battery, so they form a closed loop. Most circuits have devices such as light bulbs that convert electrical energy to other forms of energy. ... When the switch is turned on, the circuit is closed and current can flow through it.

Explanation:

4 0
3 years ago
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3. A model rocket takes 0.05 seconds to speed up from rest to its maximum velocity of 80 m/s.
nikklg [1K]

Answer:

1600 \frac{m}{s^2}

Explanation:

Acceleration is defined as the change in velocity divided by the time it took to produce such change. The formula then reads:

a = \frac{change-in-velocity}{time} = \frac{Vf-Vi}{t}

Where Vf is the final velocity of the object, (in our case 80 m/s)

Vi is the initial velocity of the object (in our case 0 m/s because the object was at rest)

and t is the time it took to change from the Vi to the Vf (in our case 0.05 seconds.

Therefore we have:

a = \frac{80 m/s - 0 m/s}{0.05 sec} = 1600 \frac{m}{s^2}

Notice that the units of acceleration in the SI system are \frac{m}{s^2} (meters divided square seconds)

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