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nirvana33 [79]
3 years ago
11

Why do objects move at constant speed

Physics
1 answer:
kati45 [8]3 years ago
7 0
Most objects move at a constant speed because of friction and acceleration. The constant speed keeps them in place, and keeps a balance. 
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Martin has severe myopia, with a far point on only 17 cm. He wants to get glasses that he'll wear while using his computer whose
marusya05 [52]

Answer:

Explanation:

Far point = 17 cm . That means he can not see beyond this distance .

He wants to see at an object at 65 cm away . That means object placed at 65 has image at 17 cm by concave lens . Using lens formula

1 / v - 1 / u = 1 / f

1 / - 17 - 1 / - 65 = 1 / f

= 1 / 65 - 1 / 17

= -  .0434 = 1 / f

power = - 100 / f

= - 100 x .0434

= - 4.34 D .

6 0
4 years ago
Physics laws of motion
expeople1 [14]

The acceleration is 0.095 m/s^2

Explanation:

We can solve the problem by applying Newton's second law of motion: in fact, the net force acting on an object is equal to the product between the mass of the object and its acceleration. Therefore we can write:

\sum F = ma

where:

\sum F is the resultant force acting on the object

m is its mass

a is its acceleration

In this problem, we have the following forces acting on the system:

F_1 = 2500 N (forward)

F_2 = -2400 N (backward)

So, Newton's second law can be rewritten as:

F_1 -F_2 = ma

where:

m = 1050 kg is the mass of all the students

Solving the formula for a, we find the acceleration of the system:

a=\frac{F_1-F_2}{m}=\frac{2500+(-2400)}{1050}=0.095 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
How did Niels Bohr change the atomic model based on his experimental results?
Alexus [3.1K]

Answer: Find the answer in the explanation

Explanation:

Bohr postulated that :

1.) Electrons revolve in specific circular orbits around the nucleus and these orbits can be represented by the letters K, L, M, N.

2.) Electrons revolving in a particular orbit are in a stationary state. They can neither gain energy nor loose energy. 3.) But if an electron jumps from an higher orbit to a lower orbit it will emit energy in the form of radiations. Also if an electron jumps from lower orbit to a higher orbit it excites and absorbs energy in the form of radiations.

4.) Neil Bohr experimental findings about angular momentum of an electron shows more light on the stability of atom and the line spectrum of hydrogen atom

8 0
4 years ago
Sandra's target heart rate zone is 135bpm—172bpm. Marissa's target heart rate zone is 143bpm—176bpm. They stop playing basketbal
Feliz [49]

Answer: Neither Sandra nor Marissa will be in her THR zone.


Explanation:


1) Actual pulse of both Sandra and Marissa : 144 bpm


2) Decrease of 20 bpm ⇒ 144 bpm - 20 bpm = 124 bpm


3) Sandra's TRH is in the range 135 - 172 bpm.


Since 124 < 135, she will be below the range.


4) Marissa's TRH range is 143 - 176 bpm.


Since, 124 < 143, she is below the range


In conlusion, neither Sandra nor Marissa will be in her THR zone.

6 0
3 years ago
Read 2 more answers
a. A beam of light is incident from air on the surface of a liquid. If the angle of incidence is 26.7° and the angle of refracti
Diano4ka-milaya [45]

Answer:

(a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

Explanation:

Given that,

Incidence angle = 26.7°

Refraction angle = 18.3°

(a). We need to calculate the refraction of liquid

Using Snell's law

n=\dfrac{\sin i}{\sin r}

Put the value into the formula

n=\dfrac{\sin 26.7}{\sin 18.3}

n=1.43

We need to critical angle for the liquid when surrounded by air

Using formula of critical angle

C=\sin^{-1}(\dfrac{1}{n})

Put the value into the formula

C=\sin^{-1}(\dfrac{1}{1.43})

C=44.37^{\circ}

(b). Given that,

Incidence angle = 37.5°

Speed of light in mineral v=2.17\times10^{8}\ m/s

We need to calculate the index of refraction

Using formula of index of refraction

n=\dfrac{c}{v}

Put the value into the formula

n=\dfrac{3\times10^{8}}{2.17\times10^{8}}

n=1.38

We need to calculate the angle of refraction

Using Snell's law

n=\dfrac{\sin i}{\sin r}

\sin r=\dfrac{\sin i}{n}

Put the value into the formula

\sin r=\dfrac{\sin 37.5}{1.38}

r=\sin^{-1}(\dfrac{\sin 37.5}{1.38})

r=26.17^{\circ}

Hence, (a). The critical angle for the liquid when surrounded by air is 44.37°

(b). The angle of refraction is 26.17°.

3 0
3 years ago
Read 2 more answers
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