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nirvana33 [79]
3 years ago
11

Why do objects move at constant speed

Physics
1 answer:
kati45 [8]3 years ago
7 0
Most objects move at a constant speed because of friction and acceleration. The constant speed keeps them in place, and keeps a balance. 
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Why doesn’t a ball roll on forever after being kicked at a soccer game?
Dimas [21]

Answer:

Because it is being stopped by another person

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3 years ago
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What force is needed to accelerate an object 5 m/s if the object has a mass of 10kg?
nevsk [136]
The <span>force that is needed to accelerate an object 5 m/s if the object has a mass of 10kg 50N because you multiply 5 and 10</span>
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What's the difference and similarity between O2 and 2 O ?
nasty-shy [4]
O2 refers to two oxygen atoms bonded together, while 2 O refers to two oxygen atoms that are not bonded to each other. They both have two oxygen atoms, but in O2, the oxygen atoms are bonded, while in 2O, the atoms are not.
4 0
3 years ago
Which atomic number is the threshold value below which fusion may occur?
Luda [366]

Answer:

The atomic number 26(iron) is the threshold value below which the fusion might occur.

Explanation:

Nuclear fusion is a reaction in which two or more nuclei are combined to form one or more different atomic nuclei and subatomic particles.

Energy released in a fusion reaction is because of a key feature of nuclear matter called the binding energy which is a measure of the efficiency with which its constituent nucleons are bound together.

As we go up in atomic number, the energy released per nuclei goes down until it hits a minimum which is for atomic number 26 (iron) and fusion is not possible.

7 0
3 years ago
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In an experiment, a large number of electrons are fired at a sample of neutral hydrogen atoms and observations are made of how t
kakasveta [241]

Answer:

N = 1036 times

Explanation:

The radial probability density of the hydrogen ground state is given by:

p(r) = \frac{4r^{2} }{a_{0} ^{3} } e^{\frac{-2r}{a_{0} } }

p(\frac{a_{0} }{2} ) = \frac{4(\frac{a_{0} }{2} )^{2} }{a_{0} ^{3} } e^{\frac{-2(\frac{a_{0} }{2} )}{a_{0} } }

p(2a_{0} ) = \frac{4(2a_{0}) ^{2} }{a_{0} ^{3} } e^{\frac{-4a_{0} }{a_{0} } }

N = 1300\frac{p(2a_{0}) }{p(\frac{a_{0} }{2} )}

N = 1300\frac{(2a_{0}) ^{2}e^{\frac{-4a_{0} }{a_{0} } }  }{(\frac{a_{0} }{2} )^{2} e^{\frac{-a_{0} }{a_{0} } }}

N = 1300(16) e^{-3}

N = 1035.57

N = 1036 times

6 0
3 years ago
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