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enyata [817]
3 years ago
15

A bullet enters the left lung and collapses it. Which cavity has been entered? Multiple Choice Cranial Pericardial cavity Pleura

l cavity Vertebral canal Mediastinum
Physics
1 answer:
Ksivusya [100]3 years ago
6 0

Answer:

Pleural cavity

Explanation:

Pleural cavity is thin fluid filled space that surrounds the lungs and provide lubrication during the expansion and contraction. So if the bullet enters the left lung then it has been entered in the pleural cavity.

Pericardial cavity contains heart and other blood vessals so it is not the right option. Mediastinum is the area between the lungs that contains the heart parts so it not the right option too. Then comes the vertebral canal also known as spinal cord so it has nothing to do with the lungs. Hence the correct option is Pleural cavity.

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A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on
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Answer:

The work required is -515,872.5 J

Explanation:

Work is defined in physics as the force that is applied to a body to move it from one point to another.

The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.

Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:

Ec=\frac{1}{2} *m*v^{2}

where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).

The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:

W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}

W=\frac{1}{2} *m*(v2^{2}-v1^{2})

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W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})

W= -515,872.5 J

<u><em>The work required is -515,872.5 J</em></u>

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