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olga_2 [115]
3 years ago
8

What is the SST for the data set (1,4), (2,6),(4,11)?

Mathematics
2 answers:
andrey2020 [161]3 years ago
6 0

Answer:

26

Step-by-step explanation:

SST = ∑ ( y − ȳ ) ² (ȳ = pronounced y bar is the mean of y values)

ȳ = (4+6+11)/3 = 21/3 = 7

∑ ( y − ȳ ) ² =  ( 4 − 7 ) ² +  ( 6 − 7 ) ² +  ( 11 − 7 ) ²

=  (  − 3 ) ² +  (  - 1 ) ² +  ( 4 ) ²

= 9 + 1 + 16

= 26

densk [106]3 years ago
5 0

Answer: 26

Step-by-step explanation:

First Data: (4 - 7)^2

Second data: (6 - 7)^2

Third Data: (11 - 7)^2

So the SST is (4 - 7)^2 + (6- 7)^2 + (11 - 7)^2 = 9 + 1 + 16 = 26

Hope this helps! :)

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Hello from MrBillDoesMath!

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=> 2 tens + 13 ones  = 20 + 13 = 33

Thank you,

MrB

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\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill


\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}


now that we know how long each one is, let's plug those in Heron's Area formula.


\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18

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3 years ago
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