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3 years ago

Factor 9y2 - 12y + 4. (3y - 2)2 (3y - 2)(3y + 2) (3y - 4)(y + 1)

Mathematics

1 answer:

serious [3.7K]3 years ago

8 0

(3y)^2-2*3y*2+2= 9y^2-12y+4

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Subtract: 3/4y-(1/2y+1/3)

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Answer: y=72

Step-by-step explanation:

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3 years ago

Write and solve an inequality for the following. As a salesperson you are paid $75 a week plus $3 per sale. This week you want t

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Answer:

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Step-by-step explanation:

150-75=75

75/3=25

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3 years ago

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3 years ago

Complete the equation of the line through (2, 1) and (5, -8). Use exact numbers. y =

TEA [102]

Answer:

Step-by-step explanation:

given: (2,1) & (5-8)

first find the slope,

m= (Y2-Y1) / (X2-X1)

m=(-8-1)/(5-2)

m=(-9)/(3)

m=-3

we have y=-3x+b

use any point to sub in x and y

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4 0

3 years ago

Read 2 more answers

A truck travels 500 miles at an average speed of 60 miles per hour on a return trip on the same route and travels at an average

marta [7]

The return trip took 1 hour 42 minutes longer

Further explanation:

The distance will remain same on return.

The formula for speed is given by:

$Speed=\frac{Distance}{Time}$

Let d be the distance

s1 be the speed while going and s2 be the speed while returning

and

t1 be the time while going and t2 be the time while returning

d=500 miles

s1=60 miles per hour

s2=50 miles per hour

We have to calculate time for both trips,

So,

Time while Going:

$s_1=\frac{d}{t_1}\\t_1=\frac{d}{s_1}$

Putting the values of d and s1

$t_1=\frac{500}{60}\\=8.3\ hours$

Converting 8.3

8 will be the hours,

for 0.3 hour

0.3*60=18 minutes

The first trip took 8 hours and 18 minutes.

Time while returning:

$s_2=\frac{d}{t_2}\\t_2=\frac{d}{s_2}$

Putting the values of d and s1

$t_2=\frac{500}{50}\\=10\ hours$

The difference of both times is: 1 hour 42 minutes

So,

The return trip took 1 hour 42 minutes longer

Keywords: Time, Distance, Speed

Learn more about movement at:

#LearnwithBrainly

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3 years ago