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Varvara68 [4.7K]
3 years ago
6

As the period number increases on the periodic table (moving from the top of the table to the bottom), A. the atomic number incr

eases and the atomic mass decreases. B. the atomic number decreases and the atomic mass increases. C. the number of the principal energy level containing the outer electrons increases. D. the number of the principal energy level containing the outer electrons decreases.
Chemistry
2 answers:
melamori03 [73]3 years ago
8 0

Answer:

The correct option is C. the number of the principal energy level containing the outer electrons increases.

Explanation:

Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number Z. In the periodic table the elements are placed according to their atomic numbers, in order, in an increasing manner and are represented by the symbol, coming from His name in Latin. You can distinguish horizontal divisions or rows called periods and vertical divisions or columns that are called groups.

The table is divided into periods that are listed from 1 to 7 from top to bottom. Elements that belong to the same period have different properties, but similar masses, because they have the same number of orbitals. That is, the elements that belong to the same period have their electrons arranged in the same number of energy levels. For example, an element with five electronic layers will be located in the fifth period. Then, as the period number increases in the periodic table, the number of the energy level increases, that is, the electronic layer.

<u><em>Then, the correct option is C. the number of the principal energy level containing the outer electrons increases.</em></u>

natka813 [3]3 years ago
3 0

C) the number of the pricipal energy level containing the outer electrons increases

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Answer:

The fingers refer to Atomic number of each element.

Explanation:

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3 years ago
How many milliliter of a solution of 4.00KI are needed to prepare 250.0mL of 0.760 KI
Alexeev081 [22]
Answer:

47.5 mL

Solving:

M1 = 4.00 M

V1 = ?

M2 = 0.760 M

V2 = 0.250 L

---

M1 * V1 = M2 * V2

V1 = ( M2 * V2 ) / M1

V1 = ( 0.760 * 0.250 ) / 4.00

V1 = ( 0.190 ) / 4.00

V1 = 0.0475 L
3 0
4 years ago
Potassium thiocyanate, KSCN, is often used to detect the presence of Fe3+ ions in solution through the formation of the red Fe(H
Natalija [7]

Answer:

Ferric ions left in the solution at equilibrium is 8.0\times 10^{-6} M.

Explanation:

Moles of ferric nitrate in 0.700 L = n

Volume of the solution = V = 0.700 L

Molarity of ferric nitrate = M = 0.00150 M

n=M\times V=0.00150 M\times 0.700 L=0.00105 mol

Moles of potassium thiocyanate in 0.700 L = n'

Volume of the potassium thiocyanate solution = V' = 0.700 L

Molarity of potassium thiocyanate = M' = 0.200 M

n'=M'\times V'=0.200 M\times 0.700 L=0.140 mol

Molarity of ferric ions after mixing :

1 mol of ferric nitrate gives 1 mol of ferric ions.Then 0.00105 mol ferric nitrate will :

Moles of ferric ions = 0.00105 mol

M_1=\frac{0.00105 mol}{0.700 L+0.700 L}=0.00075 M

Molarity of  thiocyanate ions after mixing :

1 mol of potassium thiocyanate gives 1 mol of thiocyanate ions.Then 0.140 mol potassium thiocyanate will give:

Moles of thiocyanate ions = 0.140 mol

M_2=\frac{0.140 mol}{0.700 L+0.700 L}=0.1 M

Complex equation:

          Fe^{3+}+SCN^-\rightleftharpoons [Fe(SCN)]^{2+}

0.00075 M         0.1 M                        0

At equilibrium:

(0.00075 M -x)    (0.1 M-x)                  x

The formation constant of the given complex =K_f=8.9\times 10^2

K_f=\frac{[[Fe(SCN)]^{2+}]}{[[Fe^{3+}]][SCN^{-}]}

8.9\times 10^2=\frac{x}{(0.00075 M -x)\times (0.1 M-x)}

Solving for x:

x = 0.000742 M

Ferric ions left in the solution at equilibrium :

= (0.00075 M -x) = (0.00075 M - 0.000742 M)= 8.0\times 10^{-6} M

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Answer:

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You have to post the table
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